1. Three blocks, with masses m1 5.10 kg, and m3 kg, are pulled on a horizontal frictionless surface by a 19.00 N force that makes a 28° angle (0) with the horizontal (see figure). What is the magnitude of the tension between the m2 and m3 blocks? N m3 = 5.60 kg, m2 m₂ m₁ = = 7.80
1. Three blocks, with masses m1 5.10 kg, and m3 kg, are pulled on a horizontal frictionless surface by a 19.00 N force that makes a 28° angle (0) with the horizontal (see figure). What is the magnitude of the tension between the m2 and m3 blocks? N m3 = 5.60 kg, m2 m₂ m₁ = = 7.80
College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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![**Problem Statement:**
1. Three blocks, with masses \( m_1 = 5.60 \, \text{kg} \), \( m_2 = 5.10 \, \text{kg} \), and \( m_3 = 7.80 \, \text{kg} \), are pulled on a horizontal frictionless surface by a 19.00 N force that makes a 28° angle (θ) with the horizontal (see figure). What is the magnitude of the tension between the \( m_2 \) and \( m_3 \) blocks?
\[ \boxed{} \, \text{N} \]
**Diagram Explanation:**
- **Blocks Arrangement:**
- There are three blocks aligned horizontally on a frictionless surface.
- From left to right in the figure, the blocks are labeled \( m_3 \), \( m_2 \), and \( m_1 \).
- **Connections:**
- The blocks are connected by strings:
- One string connects \( m_3 \) to \( m_2 \).
- Another string connects \( m_2 \) to \( m_1 \).
- **Applied Force:**
- An external force \(\overrightarrow{F}\) of 19.00 N is applied to the system.
- This force is at an angle of 28° (θ) with respect to the horizontal axis.
- **Force Components:**
- The horizontal component of the applied force \( \overrightarrow{F} \) can be resolved as \( F \cos(θ) \).
- The vertical component \( F \sin(θ) \) does not affect the horizontal motion because the surface is frictionless.
**Objective:**
- Determine the tension between the blocks \( m_2 \) and \( m_3 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd0a9c9c-b0c8-47bb-88dc-3ac08f167320%2F0fd9dee9-4090-473e-b264-46f1525a5b3f%2F71ek07v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
1. Three blocks, with masses \( m_1 = 5.60 \, \text{kg} \), \( m_2 = 5.10 \, \text{kg} \), and \( m_3 = 7.80 \, \text{kg} \), are pulled on a horizontal frictionless surface by a 19.00 N force that makes a 28° angle (θ) with the horizontal (see figure). What is the magnitude of the tension between the \( m_2 \) and \( m_3 \) blocks?
\[ \boxed{} \, \text{N} \]
**Diagram Explanation:**
- **Blocks Arrangement:**
- There are three blocks aligned horizontally on a frictionless surface.
- From left to right in the figure, the blocks are labeled \( m_3 \), \( m_2 \), and \( m_1 \).
- **Connections:**
- The blocks are connected by strings:
- One string connects \( m_3 \) to \( m_2 \).
- Another string connects \( m_2 \) to \( m_1 \).
- **Applied Force:**
- An external force \(\overrightarrow{F}\) of 19.00 N is applied to the system.
- This force is at an angle of 28° (θ) with respect to the horizontal axis.
- **Force Components:**
- The horizontal component of the applied force \( \overrightarrow{F} \) can be resolved as \( F \cos(θ) \).
- The vertical component \( F \sin(θ) \) does not affect the horizontal motion because the surface is frictionless.
**Objective:**
- Determine the tension between the blocks \( m_2 \) and \( m_3 \).
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