1. Three blocks are connected by a weightless cord and rest on an inclined plane. Using Newton's second law of motion, this yields the following set of simultaneous equations (free-body diagrams are shown in Fig. 1.4b): 96 692.96 100 kg 45° 346.48 a, acceleration 50 kg (a) 692.96 X 692.96 x 0.25 = 173.24 25 kg 417324 x 0.375 = 64.97 1346.48 x 0.375 = 129.93 173.24 173.24 25 x 9.8 = 245 692.96 346.48 T 100 x 9.8 980 50 x 9.8 - 490 (b) Fig. 1.4 100a + T = 519.72 50a-T + R = 216.55 25a R 108.28 Solve for acceleration a and the tensions T and R in the two ropes. Use Gaussian elimination method.
1. Three blocks are connected by a weightless cord and rest on an inclined plane. Using Newton's second law of motion, this yields the following set of simultaneous equations (free-body diagrams are shown in Fig. 1.4b): 96 692.96 100 kg 45° 346.48 a, acceleration 50 kg (a) 692.96 X 692.96 x 0.25 = 173.24 25 kg 417324 x 0.375 = 64.97 1346.48 x 0.375 = 129.93 173.24 173.24 25 x 9.8 = 245 692.96 346.48 T 100 x 9.8 980 50 x 9.8 - 490 (b) Fig. 1.4 100a + T = 519.72 50a-T + R = 216.55 25a R 108.28 Solve for acceleration a and the tensions T and R in the two ropes. Use Gaussian elimination method.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:1. Three blocks are connected by a weightless cord and rest on an inclined plane. Using
Newton's second law of motion, this yields the following set of simultaneous equations
(free-body diagrams are shown in Fig. 1.4b):
96
692.96
100 kg
45°
346.48
a, acceleration
50 kg
(a)
692.96 X
692.96 x 0.25 = 173.24
25 kg
417324 x 0.375 = 64.97
1346.48 x 0.375 = 129.93
173.24
173.24
25 x 9.8 = 245
692.96
346.48
T
100 x 9.8 980
50 x 9.8 - 490
(b)
Fig. 1.4
100a + T = 519.72
50a-T + R = 216.55
25a R
108.28
Solve for acceleration a and the tensions T and R in the two ropes. Use Gaussian
elimination method.
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