PLEASE ANSWER NO.3 . SHOW THE DETAILED SOLUTION. THANK YOU AND GOD BLESS.SUBJECT: DYNAMICS OF RIGID BODIES CE 2111 DYNAMICS OFF RIGID BODIES MQ 1Solve each problem neatly and completely.Write all numerical answers to the nearest 3rddecimal and with the correct simplified unitsotherwise your answers will not be considered.1. The velocity of a particle moving along thex-axis is defined by v=x³-4x² + 6x where v isin ft/s and x is in ft. Compute the value ofthe acceleration when x=2ft.2. The position of a particle moving along ahorizontal line is given by the equationS-41²-21t² + 18t-4, where s is thedistance from the origin and t is the time inseconds. The particle is 3 feet to the rightof the origin when t= Is. Determine:a.the time when the velocity is zerob. the acceleration when t=25, and3. A stone is projected vertically upwardfrom the top of a 120-m high tower at avelocity of 36 m/s.Determine the maximum height it.attained by the stone measuredfrom the ground.b. How long will it take the stone toreach the top?How long will it take the stone toreach the ground?d. With what velocity will it hit theground?

“Since you have asked multiple questions, we will solve the first question for you. If you want any…

Answered: 1. The velocity of a particle moving…

1. The velocity of a particle moving along the x-axis is defined by v-x³-4x² + 6x where v is in ft/s and x is in ft. Compute the value of the acceleration when x =2ft.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

PLEASE ANSWER NO.3 . SHOW THE DETAILED SOLUTION. THANK YOU AND GOD BLESS.

SUBJECT: DYNAMICS OF RIGID BODIES

CE 2111 DYNAMICS OFF RIGID BODIES MQ 1
Solve each problem neatly and completely.
Write all numerical answers to the nearest 3rd
decimal and with the correct simplified units
otherwise your answers will not be considered.
1. The velocity of a particle moving along the
x-axis is defined by v=x³-4x² + 6x where v is
in ft/s and x is in ft. Compute the value of
the acceleration when x=2ft.
2. The position of a particle moving along a
horizontal line is given by the equation
S-41²-21t² + 18t-4, where s is the
distance from the origin and t is the time in
seconds. The particle is 3 feet to the right
of the origin when t= Is. Determine:
a.
the time when the velocity is zero
b. the acceleration when t=25, and
3. A stone is projected vertically upward
from the top of a 120-m high tower at a
velocity of 36 m/s.
Determine the maximum height it.
attained by the stone measured
from the ground.
b. How long will it take the stone to
reach the top?
How long will it take the stone to
reach the ground?
d. With what velocity will it hit the
ground?

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