Please help me with this one. Please use the second photo as reference.Subject: Strength of materialsTopic: Torsion |- wfat is the minimum diameter Hà foliaSteel shaft that ll not twist thru morethan 3° into a torque t 12kn.m? what raxinumshearing stress is de velop ed 7 Use G- 83 Gpaà 6-m lingtk. mhen fubjectedl TORSIONEquations of compatibility – relations between stresses that are compatible withthe deformations.Equations of equilibrium – relations between the stresses resulting from a studyof the equilibrium between externally applied loads and the internal resistingforces over an exploratory section.Torsion Formulas0 = TL/JG0- angle of rotation (radians)T-torque (N-m)L- length (m)J- polar moment of inertia (m")G- modulus of rigidity (N/m)If we wish to express O in degrees, we multiply the right-hand member by the unitfraction, 180°/r rad = 57.3° /radBy replacing the product GO/L by its equivalent value T/J:T = Tp/JThis is called the torsion formula.The formula that determines the maximum shearing stress is a more commonform of the torsion formula. It is obtained by replacing p by the radius r ofthe shaft:Max t = Tr/J1. The stresses must not exceed the shearing proportional limit.2. The formulas are applicable only to circular shafts, either solid or hollow.

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Answered: -Wfat is the minimum diamefer Ha folid…

-Wfat is the minimum diamefer Ha folid Steel shaft that ll not twist thru more than 3° in á G-m Cingth mhen fubjected to a torque y 12kn.m? wfat mainum shearing stress is develop el? Use G- 83 Gpa

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Chapter9: Composite Construction

Section: Chapter Questions

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Analysis and Procedures for Material Selection

The term material selection means to select the right material for various engineering applications. There are various engineering materials available and each has different individual properties. Thorough knowledge of the material properties and behavior is crucial in the design process. For instance, a structural member, such as a beam, is used to support vertical shear loads by the building itself. To withstand such loads, the material of the beam must possess adequate strength and stiffness to resist any deformation that might lead to the formation of cracks.

Question

Please help me with this one. Please use the second photo as reference.

Subject: Strength of materials

Topic: Torsion

|- wfat is the minimum diameter Hà folia
Steel shaft that ll not twist thru more
than 3° in
to a torque t 12kn.m? what raxinum
shearing stress is de velop ed 7 Use G- 83 Gpa
à 6-m lingtk. mhen fubjectedl

TORSION
Equations of compatibility – relations between stresses that are compatible with
the deformations.
Equations of equilibrium – relations between the stresses resulting from a study
of the equilibrium between externally applied loads and the internal resisting
forces over an exploratory section.
Torsion Formulas
0 = TL/JG
0- angle of rotation (radians)
T-torque (N-m)
L- length (m)
J- polar moment of inertia (m")
G- modulus of rigidity (N/m)
If we wish to express O in degrees, we multiply the right-hand member by the unit
fraction, 180°/r rad = 57.3° /rad
By replacing the product GO/L by its equivalent value T/J:
T = Tp/J
This is called the torsion formula.
The formula that determines the maximum shearing stress is a more common
form of the torsion formula. It is obtained by replacing p by the radius r of
the shaft:
Max t = Tr/J
1. The stresses must not exceed the shearing proportional limit.
2. The formulas are applicable only to circular shafts, either solid or hollow.

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