Sheet No. Ten1. the temperature in evaporator coil is -6 °C and that in the condenser coil is 22 °C.assuming that the machine operates on the reversed carnot cycle. Calculate the COPthe refrigeration effect per kW of input work, and the heat rejected to the condenser.(9.54;9.54kW;10.4kW)2. a Carnot refrigeration cycle absorbs heat at (-12 °C) and rejects it at 40 °C a-calculate the CoP of this cycle d- If the cycle is absorbing 15 kW at (-12 °C)temperature, how much power is required.3. a refrigeration system using R-22 is to have a refrigerating capacity of 80 kW. Thecycle is standard vapour compression cycle( dry saturated vapour at compressor inlet)in which the evaporation temperature is (-8°C) and the condensing temperature 42 °Ca- determine the volume flow of refrigerant measured in cubic meter per second at theinlet to the compressor. B- calculate the power required by the compressor. C-at theentrance to the evaporator what is the fraction of vapour in the mixture expressed bothon mass basis and volume basis(0.292,0.971)4. The capacity of a refrigerator is 200 TR when working between - 6°C and 25.C. Determine themass of ice produced per day from water at 25°C. Also find the power required to drive theunit. Assume that the cycle operates on reversed Carnot cycle and latent heat of ice is 335kJ/kg.5. Refrigerant-134a is the working fluid in an ideal compression refrigeration cycle. Therefrigerant leaves the evaporator at -20°C and has a condenser pressure of 0.9 MPa.The mass flow rate is 3 kg/min. Find COPR and COPR, Camot for the same Tmax andTmin , and the tons of refrigeration6.

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1. the temperature in evaporator coil is -6 °C and that in the condenser coil is 22 °C. assuming that the machine operates on the reversed carnot cycle. Calculate the COP the refrigeration effect per kW of input work, and the heat rejected to the condenser. (9.54;9.54KW;10.4kW)

1. the temperature in evaporator coil is -6 °C and that in the condenser coil is 22 °C. assuming that the machine operates on the reversed carnot cycle. Calculate the COP the refrigeration effect per kW of input work, and the heat rejected to the condenser. (9.54;9.54KW;10.4kW)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Example 2: Refrigerant R-134a enter the compressor of a has a refrigerantor a superheared vapor at 0.14MPa and -10°C at arate of 0.05kg/sec and leave at 0.8Mp and 50°C.The refrigerant cooled in the condenser to 26°C and 0.72Mpa is throttled to 0.15MPa.Disregradingany heat transfere and pressure drop in the connecting line between the components. Determine: a) The rate of heat removed from the refrigerated space b) The power input to the compressor. c) Isentropic eff of the compressor d) COP of the refrigerantor.
Define C.O.P. of the simple vapor compression refrigeration cycle R-717. The evaporation temperature is -15 ° C and the condenser temperature is 40 ° C. COP =
750 kPa 800 kPa 55°C Condenser (3) Expansion valve Compressor Evaporator Figure 3 4. The liquid leaving the condenser of a 30 kW heat pump using refrigerant 134a as the working fluid is subcooled by 5.4°C. The condenser operates at 1 MPa and the evaporator at 0.4 MPa. How does this subcooling change the power required to drive the compressor as compared to an ideal vapour-compression refrigeration cycle? (3.41 kW, 3.25 kW)
a commercial refrigerator using isobutane (r600a) operates on the simple saturation cycle with saturated suction and discharge temperature of "-25" °c and 55 °c respectively: (a) calculate the cop and power required to run the compressor per ton of refrigeration. (b) if the liquid is subcooled by 10 °c in the condenser, calculate the cop and power required to run the compressor per ton of refrigeration.
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The following information is provided for a refrigerator operating on the a vapor-compression refrigeration cycle with R-134a: High pressure: 800 kPa Low pressure: 160 kPa Compressor exit temperature: 50 °C The work required to run the refrigerator per kg of refrigerant is?
An r-134a refrigerator operates a simple vapor compression cycle (SVCC). The evaporatoroperates at -10 °C, while the condenser operates at 1 MPa. R-134a flows around the system at 10 g/s.a. Graph the cycle in a P-h diagram and calculate the temperature at the exit of the compressor, assuming it is 100% isentropicallyefficient.b. Calculate the power required by the compressor (in W) and the cooling effect of the refrigerator (in kW) c. Compute for the COP of the system. What is its percent difference from the reversible efficiency?
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Q.6 A vapor compression cycle uses R134a as the refrigerant . The vapor condenses at 40 degrees * C and is subcooled to 35 degrees * C before entering the expansion valve . The evaporating temperature is - 5 degrees * C . The vapor leaving the evaporator is superheated to 5 degrees * C at entry to the compressor . The heat absorption rate is 13 kW and the compression process is isentropic . Calculate (i) the refrigerant flow rate, (ii ) the work input , and ( iii ) the COP . Answers: () 0.0837kg * s ^ - 1 , (ii) 2.63 kW , (iii) 4.95