1. The probability of finding a free electron is given by the Fermi energy function f(E) as: 1 f(E) E – EF e +1 (1) EF is Fermi energy, KB is Boltzmann's constant (1/38 ×10 -23 J/K), and T is the absolute temperature of the solid. Find f (E), when a. T=0 and E< EF

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Chapter1: Units, Trigonometry. And Vectors
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The probability of finding a free electron is given by the Fermi energy function \( f(E) \) as:

\[ f(E) = \frac{1}{e^{\left(\frac{E - E_F}{k_B T}\right)} + 1} \]

where \( E_F \) is the Fermi energy, \( k_B \) is Boltzmann’s constant \((1/38 \times 10^{-23} \, \text{J/K})\), and \( T \) is the absolute temperature of the solid. Find \( f(E) \) when:

a. \( T = 0 \) and \( E \leq E_F \)

b. \( T = 0 \) and \( E > E_F \)

c. \( T > 0 \) and \( E = E_F \)
Transcribed Image Text:The probability of finding a free electron is given by the Fermi energy function \( f(E) \) as: \[ f(E) = \frac{1}{e^{\left(\frac{E - E_F}{k_B T}\right)} + 1} \] where \( E_F \) is the Fermi energy, \( k_B \) is Boltzmann’s constant \((1/38 \times 10^{-23} \, \text{J/K})\), and \( T \) is the absolute temperature of the solid. Find \( f(E) \) when: a. \( T = 0 \) and \( E \leq E_F \) b. \( T = 0 \) and \( E > E_F \) c. \( T > 0 \) and \( E = E_F \)
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