1. The following frequency distribution of marks has mean 4.5. Mark 1 3 Frequency 2 6 (a) Find the value of x. 2+8+18 +36 +5x +54 +88 2+4+6+9rx+gey (b) Write down the standard deviation. 1.56 24 4 5 X 9 1465x 94 4x 6 6 7 4 = 1.5 146 +5x-153 +4.5 0.5x=7 x 14
1. The following frequency distribution of marks has mean 4.5. Mark 1 3 Frequency 2 6 (a) Find the value of x. 2+8+18 +36 +5x +54 +88 2+4+6+9rx+gey (b) Write down the standard deviation. 1.56 24 4 5 X 9 1465x 94 4x 6 6 7 4 = 1.5 146 +5x-153 +4.5 0.5x=7 x 14
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:1.
The following frequency distribution of marks has mean 4.5.
Mark
I
2
3
4
2
Frequency
4
9
6
(a)
Find the value of x.
146 15x
2+8+18 +36 +5x +54 + 28
2+4+6+9rxegey
94 +x
(b) Write down the standard deviation.
1.56
2.
The following table gives the examination grades for 120 students.
Grade
Number of students
1
9
2
25
35
9
11
(a)
3
4
5
Find the value of
p: 34 +35 - 69
(ii) q. 109-69 = 40
(b) Find the mean grade.
3.16
(c) Write down the standard deviation.
1.09
2
5
x
6
7
4
= 1.5
146 +5x-153 +4.5
0.5x²7
x = 14
Cumulative frequency
9
34
Р
109
120
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