Answered: 5. 4. 7. 3. 9. 5. I know the mean for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Scores of on a math test were normally distributed with a mean of 82 and a standard deviation of 6. What percentage of the scores that is more than 90? Show your works and read the table.
Suppose X - N (8, 2). Between what a values does 68.22% of the data lie? The range of x values is centered at the mean of the distribution (i.e., 8). Enter your answers in increasing order, to the nearest integer. 68.22% of the data lie between Number and Number
It known that the average number of drop out per month 2.3. If you would like to predict the number of dropouts in a year, then the Poisson rate is?
The graph illustrates the distribution of test scores taken by College Algebra students. The maximum possible score on the test was 130, whille the mean score was 79 and the standard deviation was 11. (34,13.5,2.35,0.15) భాతు 46 57 68 79 90 101 112 Distribution of Test Scores What is the approximate percentage of students who scored between 79 and 112 on the test? What Is the approximate percentage students who scored between 68 and 90 on the test? What Is the approximate percentage of students who scored between 68 and 79? 96 What is the approximate percentage of students who scored less than 57 on the test?
The graph illustrates the distribution of test scores taken by College Algebra students. The maximum possible score on the test was 140, while the mean score was 73 and the standard deviation was 15. 38 73 Distribution of Test Scores 28 43 103 118 What is the approximate percentage of students who scored higher than 118 on the test? % What is the approximate percentage students who scored between 58 and 88 on the test? What is the approximate percentage of students who scored less than 43 on the test? What is the approximate percentage of students who scored between 73 and 88 on the test?
The average American gets a haircut every 34 days. Is the average smaller for college students? The data below shows the results of a survey of 15 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 23, 32, 38, 31, 39, 35, 25, 30, 36, 40, 27, 23, 32, 25 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv Hi: ?vSelect an answerv c. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is 2v a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that.. O The data suggest the population mean is not significantly lower than 34 at a = 0.10, so there M 24 3. 4. 5 6. 7 EU
A right skewed data set has a mean of 35 and a standard deviation of 25. What can be said about the amount of data contained within the interval (-15, 85)? 95% of the data is within this range 68% of the data is within this range Nothing At least 75% of data is within this range
prove that If we multiply the data values by a constant (say, c), value of geometric mean will be affected. how this will affect the geometric mean? Use the equation in image to prove it, and give an example.
The graph illustrates the distribution of test scores taken by College Algebra students. The maximum possible score on the test was 140, while the mean score was 80 and the standard deviation was 13. + + + 41 54 67 80 93 106 119 Distribution of Test Scores What is the approximate percentage of students who scored between 54 and 106 on the test? What is the approximate percentage students who scored between 67 and 93 on the test? % What is the approximate percentage of students who scored between 80 and 93 on the test? %
A sample of people have their income measured in dollars per year. Robin gets a deviation of +5 on this variable. How does she compare to the sample? Her annual income is 5 standard deviations higher than the mean Her annual income is 5 dollars higher than the mean Her annual income is 5 points higher than the mean The mean of the sample is 5 thousands dollars higher than Robin’s income
I ended up with 2.28 and 3.85 and they are both wrong how do I correctly solve this problem?

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5. 4. 7. 3. 9. 5. I know the mean for that is 5.5 but how do i find the sum deviation in the data?