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1. The following data were obtained from the reaction of decomposition as follow: N₂0₁ (8)→ 4NO₂(g) + O₂(g) a. What is the order of reaction? What is the rate constant? b. c. Calculate the [N,0₁] at 150 s. d. Find the half life e. Determine the rate of reaction at 150s Exp (N,O,] (M) Time (s) 1 0.1000 0 0.0707 50 100 200 300 400 2 3 4 5 6 0.0500 0.0250 0.0125 0.00625

1. The following data were obtained from the reaction of decomposition as follow: N₂0₁ (8)→ 4NO₂(g) + O₂(g) a. What is the order of reaction? What is the rate constant? b. c. Calculate the [N,0₁] at 150 s. d. Find the half life e. Determine the rate of reaction at 150s Exp (N,O,] (M) Time (s) 1 0.1000 0 0.0707 50 100 200 300 400 2 3 4 5 6 0.0500 0.0250 0.0125 0.00625

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Complete the following questions and submit through blackboard in respective group with complete solutions 1. The following data were obtained from the reaction of decomposition as follow: N₂0₁ (8)→ 4NO₂ (g) + O₂(g) a. What is the order of reaction? b. What is the rate constant? c. Calculate the [N,0.] at 150 s. d. Find the half life e. Determine the rate of reaction at 150s Exp (N,O,] (M) Time (s) 1 0.1000 0 2 0.0707 3 0.0500 50 100 200 4 0.0250 5 0.0125 300 400 0.00625
Transcribed Image Text:Complete the following questions and submit through blackboard in respective group with complete solutions 1. The following data were obtained from the reaction of decomposition as follow: N₂0₁ (8)→ 4NO₂ (g) + O₂(g) a. What is the order of reaction? b. What is the rate constant? c. Calculate the [N,0.] at 150 s. d. Find the half life e. Determine the rate of reaction at 150s Exp (N,O,] (M) Time (s) 1 0.1000 0 2 0.0707 3 0.0500 50 100 200 4 0.0250 5 0.0125 300 400 0.00625
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