1. The following compounds or ions are aromatic. What is the Hückel number (n) for each one? Show your calculation. If more than one, give the larger n. H n = calculation

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### Aromatic Compounds and Hückel Numbers

#### Question:
1. The following compounds or ions are aromatic. What is the Hückel number (n) for each one? Show your calculation. If more than one, give the larger n.

### Diagram Descriptions:

1. **First Compound (Triangle with a positive charge):**
   - A triangular structure (three-membered ring) with a positive charge notation (+) on one vertex.

2. **Second Compound (Benzene):**
   - A six-membered carbon ring with alternating double bonds, characteristic of benzene.

3. **Third Compound (Naphthalene):**
   - A fused ring system composed of two benzene-like six-membered rings sharing a common edge.

4. **Fourth Compound:**
   - A six-membered ring with three alternating double bonds, similar to benzene.

5. **Fifth Compound (Pyrrole-like structure):**
   - A five-membered ring containing one nitrogen atom, represented as a pyrrole structure with a hydrogen attached to nitrogen and a pair of electrons indicated by a dot.

#### Hückel's Rule:
Hückel's rule states that a planar ring molecule will be aromatic if it has \(4n + 2\) π-electrons, where \(n\) is a non-negative integer (n = 0, 1, 2, 3, ...).

#### Calculations:
- For the triangular compound:
  - This compound does not fit the criteria for Hückel’s rule as it has no π-electrons.

- For benzene:
  Benzene has 6 π-electrons.
  \(4n + 2 = 6\)
  Solving for n:
  \(4n + 2 = 6 \\
  4n = 4 \\
  n = 1\)

- For naphthalene:
  Naphthalene has 10 π-electrons.
  \(4n + 2 = 10\)
  Solving for n:
  \(4n + 2 = 10 \\
  4n = 8 \\
  n = 2\)

- For the six-membered ring:
  This compound is also benzene-like and has 6 π-electrons.
  As above for benzene:
  \(n = 1\)

- For the pyrrole-like structure:
  Pyrrole has
Transcribed Image Text:### Aromatic Compounds and Hückel Numbers #### Question: 1. The following compounds or ions are aromatic. What is the Hückel number (n) for each one? Show your calculation. If more than one, give the larger n. ### Diagram Descriptions: 1. **First Compound (Triangle with a positive charge):** - A triangular structure (three-membered ring) with a positive charge notation (+) on one vertex. 2. **Second Compound (Benzene):** - A six-membered carbon ring with alternating double bonds, characteristic of benzene. 3. **Third Compound (Naphthalene):** - A fused ring system composed of two benzene-like six-membered rings sharing a common edge. 4. **Fourth Compound:** - A six-membered ring with three alternating double bonds, similar to benzene. 5. **Fifth Compound (Pyrrole-like structure):** - A five-membered ring containing one nitrogen atom, represented as a pyrrole structure with a hydrogen attached to nitrogen and a pair of electrons indicated by a dot. #### Hückel's Rule: Hückel's rule states that a planar ring molecule will be aromatic if it has \(4n + 2\) π-electrons, where \(n\) is a non-negative integer (n = 0, 1, 2, 3, ...). #### Calculations: - For the triangular compound: - This compound does not fit the criteria for Hückel’s rule as it has no π-electrons. - For benzene: Benzene has 6 π-electrons. \(4n + 2 = 6\) Solving for n: \(4n + 2 = 6 \\ 4n = 4 \\ n = 1\) - For naphthalene: Naphthalene has 10 π-electrons. \(4n + 2 = 10\) Solving for n: \(4n + 2 = 10 \\ 4n = 8 \\ n = 2\) - For the six-membered ring: This compound is also benzene-like and has 6 π-electrons. As above for benzene: \(n = 1\) - For the pyrrole-like structure: Pyrrole has
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