trans-stilbene C1H12 180.25 g/mol 50 mg NⓇ H OH Br3 Br Br stilbene dibromide C14H12Br2 340.06 g/mol yield = 80 mg KOH diphenylacetylene C14H10 178.23 g/mol yield = 35 mg a. Given that the reaction started with 50 mg and used an excess of other all other reagents, what is the percent yield for step 1? For step 2? Overall yield for both steps? b. How many grams of product (diphenylacetylene) is predicted, using the percent yield in part a, when 250 mg of trans-stilbene is used?

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3. For the following 2-step sequence,
trans-stilbene
C14H12
180.25 g/mol
50 mg
• NⓇ
H
OH
Br3
Br
Br
stilbene dibromide
C14H12Br2
340.06 g/mol
yield = 80 mg
KOH
diphenylacetylene
C14H10
178.23 g/mol
yield = 35 mg
a. Given that the reaction started with 50 mg and used an excess of other all other reagents, what is the
percent yield for step 1? For step 2? Overall yield for both steps?
b. How many grams of product (diphenylacetylene) is predicted, using the percent yield in part a, when
250 mg of trans-stilbene is used?
Transcribed Image Text:3. For the following 2-step sequence, trans-stilbene C14H12 180.25 g/mol 50 mg • NⓇ H OH Br3 Br Br stilbene dibromide C14H12Br2 340.06 g/mol yield = 80 mg KOH diphenylacetylene C14H10 178.23 g/mol yield = 35 mg a. Given that the reaction started with 50 mg and used an excess of other all other reagents, what is the percent yield for step 1? For step 2? Overall yield for both steps? b. How many grams of product (diphenylacetylene) is predicted, using the percent yield in part a, when 250 mg of trans-stilbene is used?
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