1. The diameter of the Sun is equal to 1.392 × 10⁹ m, and the distance from the Sun to Saturn is equal to 9.5 AU. Suppose you want to build an exact scale model of the solar system, and you are using a volleyball with average diameter of 21 cm to represent the Sun. a) In your scale model, how far away would Saturn be from the Sun? Give your answer in meters. b) The actual diameter of Saturn is 116,460 km. What would be Saturn's diameter in your scale model? Give your answer in centimeters.

1. The diameter of the Sun is equal to 1.392 × 10⁹ m, and the distance from the Sun to Saturn is equal to 9.5 AU. Suppose you want to build an exact scale model of the solar system, and you are using a volleyball with average diameter of 21 cm to represent the Sun. a) In your scale model, how far away would Saturn be from the Sun? Give your answer in meters. b) The actual diameter of Saturn is 116,460 km. What would be Saturn's diameter in your scale model? Give your answer in centimeters.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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1. The diameter of the Sun is equal to 1.392 × 10⁹ m, and the distance from the Sun to Saturn is equal to 9.5 AU. Suppose you want to build an exact scale model of the solar system, and you are using a volleyball with average diameter of 21 cm to represent the Sun.
2. Over several months an astronomer observes an exoplanet orbiting a distant star at a distance of 5.934 AU. Its orbit period was projected to be 3.875 years. Convert the orbit radius to meters and period to seconds. Use this information to calculate the mass M of the star in kg and solar mass units (Mo). Star Exoplanet Orbit radius (m) Orbit period (s) Star mass (kg) Star mass (Mo)
I. Directions: Complete the given table by finding the ratio of the planet's time of revolution to its radius. Average Radius of Orbit Times of Planet R3 T2 T?/R3 Revolution Mercury 5.7869 x 1010 7.605 x 106 Venus 1.081 x 1011 1.941 x 107 Earth 1.496 x 1011 3.156 x 107 1. What pattern do you observe in the last column of data? Which law of Kepler's does this seem to support? II. Solve the given problems. Write your solution on the space provided before each number. 1. You wish to put a 1000-kg satellite into a circular orbit 300 km above the earth's surface. Find the following: a) Speed b) Period c) Radial Acceleration Given: Unknown: Formula: Solution: Answer: Given: Unknown: Formula: Solution: Answer: Given: Unknown: Formula: Solution: Answer:
Tutorial Sheet One 1. Add 1 cm and 1 m. 2. Divide 3 m5 by 2 m0.5. 3. Multiply 2 ft by 4 lb. 4. Electronic communication via radio travels at approximately the speed of light (186,000 miles/second). The edge of the solar system is roughly at Pluto, which is 3.6 × 10° miles from
2. On August 27, 2003, the planet Mars was at a distance of 0.373 AU from Earth. The diameter of Mars is 6788 km. a) Calculate the angular diameter of Mars, as seen from Earth on August 27, 2003. Give your answer in arcminutes.
2. Are there any known satellites of Jupiter that are beyond the Hill sphere of Jupiter? If not, what is the largest ratio r(satellite)/r(Hill), among its satellites? 1/3 Hill Sphere Radius: RHill Rна M2 ЗМ1
Our Solar System consist of two distinctly different types of planets. A. Describe how these planets differ in their general characteristics. B. Explain the cause of these differences
Until recently, the term "planet" had no clear-cut definition. In August of 2006, leading astronomers established new guidelines and declared that Pluto is no longer a planet. Which of the following is either false or least consistent with the new guidelines? Group of answer choices Pluto is by far the largest known object in the Kuiper belt, while Eris is the largest known object in the asteroid belt. A planet must have cleared the neighborhood around its orbit. Pluto is automatically disqualified from being a planet because its oblong orbit overlaps with Neptune's. A planet must have sufficient mass for its self-gravity to overcome rigid body forces so that it assumes a nearly round shape. Pluto and the asteroid Ceres are both now classified as dwarf planets.
4. Calculate the mass of the Sun from Venus's orbital data (mass of venus= 4.87*10^24, distance is .723 AU from Sun, period is 224 Earth days). Sun Mass= KG 5. Mars Reconnaissance Orbiter (mass 2180 kg, distance is 170 miles up from the surface, its period is 112 minutes) calculate Mars mass. (Mars radius = 3.397*10^6 meters). Mass= _Kg
Use Kepler's 3rd Law and the small angle approximation. a) An object is located in the solar system at a distance from the Sun equal to 41 AU's . What is the objects orbital period? b) An object seen in a telescope has an angular diameter equivalent to 41 (in units of arc seconds). What is its linear diameter if the object is 250 million km from you? Draw a labeled diagram of this situation.
How many orders of magnitude do you need to grow in spatial scale (size) to form a planet? Let's take the extreme ends of this scale, from a dust particle of radius a = 10-6m to the gas giant Jupiter (you can round up its radius to the nearest ten to keep it simple). What else has this difference in order of magnitude? Maybe pick something that's not a length scale. Be creative!
QUESTION 1 Estimate The Temperature For A Planet In Other Solar System (Questions 1-3) Let us assume scientists just discovered a planet orbiting a star in an extra-solar system. The star has a surface temperature Ts = 10000 Kelvins and a radius Sr = 1x109 meters. Scientists also measured the distance (D) between the star and the planet as D = 2 AU - 3.0x1011 meters. The solar power per unit area from the star's surface (Ps) can be calculated from the star's surface temperature Ts (10000 Kelvins) by the Stefen-Boltzman law Ps=0(Ts)4, where o is Stefen-Boltzman constant (5.67 x 10-8 Watt/meter2/Kelvin4). What is the solar power per unit area from the star's surface (Ps)? O Ps ~ 2.87 x 108 Watt/meter2 O Ps ~ 5.67 x 108 Watt/meter2 O O Ps ~ 2.87 x 10 Watt/meter2 Watt/meter² Ps ~ 5.67 x 10⁹ QUESTION 2 The solar power (Ps) decreases from the star's surface to the distance at the planet. Assuming the solar power per unit area at the distance of the planet as Pp, we have Pp=Ps(Sr/D)2, where…