1.Suppose the weight of an adult male German Shepherd is normally distributed with a mean of 36.4 kgand a standard deviation of 4.2 kg.(a) What proportion of adult male German Shepherds will weigh more than 45 kg?(b) What is the probability a randomly selected adult male German Shepherd will weigh between 33 kgand 39 kg?(c) Twenty percent of all adult male German Shepherds have a weight less than what value?(d) Let X represent the average weight of 35 male adult male German Shepherds selected at random.What is the sampling distribution of X ? Explain.(e) What is the probability the average weight of 35 randomly selected adult male German Shepherds willbe less than 37.5 kg?(f) If the weights of adult male German Shepherds did not follow a normal distribution, would youranswers in parts (d) and (e) still be valid? Explain.2. It is estimated that 1 in 9 Canadian men will develop prostate cancer during their lifetime.(a) Consider a random sample of 180 Canadian men. Let X represent the number of these men who willeventually develop prostate cancer. What is the probability distribution of X?(b) What probability distribution can be used to approximate the probability distribution from part (a)?Explain.(c) Use your answer in part (b) to approximate the probability that at most 20 of the 180 Canadian menwill eventually develop prostate cancer.3. Refer to QUESTION 2.Consider a random sample of three Canadian men, and let P represent the proportion of these men whowill eventually develop prostate cancer. Derive the sampling distribution of P.

Given that. 1) X~N( μ , ?) μ=36.4 , ?=4.2 Z-score =( x - μ )/? NOTE:- According to bartleby…

Answered: 1. Suppose the weight of an adult male…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose per deciliter (1/10 of a liter) of blood. Suppose that after a 12-hour fast, the random variable x will have a distribution that is approximately normal with mean ? = 81 and standard deviation ? = 26. Note: After 50 years of age, both the mean and standard deviation tend to increase. For an adult (under 50) after a 12-hour fast, find the following probabilities. (Round your answers to four decimal places.) (a) x is more than 60(b) x is less than 110(c) x is between 60 and 110(d) x is greater than 125 (borderline diabetes starts at 125)
16.
3. Based on a recent study, the pH level of the arterial cord (one vessel in the umbilical cord) is normally distributed with mean 7.23 and standard deviation of 0.11. Find the percentage of preterm infants who have the following arterial cord pH levels. a. pH levels between 7.00 and7.50. b. pH levels over 7.31.
D A small amount of the trace element selenium, 50-200 micrograms (ug) per day, is considered essential to good health. Suppose that random samples of 50 adults were selected from two regions of the United States and that each person's daily selenium intake was recorded. The means and standard deviations of the selenium daily intakes for the two groups are shown in the table. Sample Mean (ug) Sample Standard Deviation (ug) Find a 95% confidence interval for the difference (₁-₂) in the mean selenium intakes for the two regions. (Round your answers to three decimal places.) 49 Region Phase One-Tw_docx 1 167.4 22.8 ug to Interpret this interval, O The probability that the difference in the average daily selenium intake for the populations in Region 1 and Region 2 is exactly in the middle of the Interval is 95%. A 2 140.5 17.3 O The probability that the difference in the average daily selenium intake for the populations in Region 1 and Region 2 is within the interval is 95%. We are 95%…
1.In a certain wildlife reserve the life span of monkey are normally distributed. The average monkey lives 20.8 years and The standard deviation is 3.1 years. Use the empirical rule to estimate the probability or percentage of a monkey living less than 23.9 years. 2. If the population of the monkey are 568, how many of them will live for less than 23.9 years. 3. IQ scores which are normallu distributed have a mean of 100 and a standard deviation of 16. The z score that corresponds to Albert IQ Is 3.75. What is his IQ?
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose per deciliter (1/10 of a liter) of blood. Suppose that after a 12-hour fast, the random variable x will have a distribution that is approximately normal with mean ? = 87 and standard deviation ? = 22. Note: After 50 years of age, both the mean and standard deviation tend to increase. For an adult (under 50) after a 12-hour fast, find the following probabilities. (Round your answers to four decimal places.) (c) x is between 60 and 110 (d) x is greater than 125 (borderline diabetes starts at 125)
Let x be a random variable that represents the pH of arterial plasma (l.e., acidity of the blood). For healthy adults, the mean of the x distribution is = 7.4.t A new drug for arthritis has been developed. However, it is thought that this drug may change blood pH. A random sample of 31 patients with arthritis took the drug for 3 months. Blood tests showed that x = 8.8 with sample standard deviations = 3.3. Use a 5% level of significance to test the claim that the drug has changed (either way) the mean pH level of the blood. A USE SALT (a) What is the level of significance? State the null and alternate hypotheses. O Hg: u + 7.4; H,: = 7.4 O Hg: H = 7.4; H,: H > 7.4 O H,: H = 7.4; H,i 7.4; H,: H = 7.4 O H: = 7.4; H,: H# 7.4 (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. O The Student's t, since the sample size is large a is known. O The standard normal, since the sample size is large and a is known. O The standard normal,…
Mf1. 7. Consider the following returns: (1) What are standard deviations of stock X and stock Y respectively? (2) What are is the correlation between stock X's return and stock Y's return? (3) Please estimate the return and standard deviation of the combination of stock X and stock Z in the equal shares
1. Among American women aged 20 to 29 years, 10% are less than 60.8 inches tall, 80% are between 60.8 and 67.6 inches tall, and 10% are more than 67.6 inches tall. Assuming that the height distribution can adequately be approximated by a normal curve, find the mean and standard deviation of the distribution.
3. The average height of a male student in the EDA class of Engr. Ventura in PLM has historically been 1.625 meters with a standard deviation of 0.07 meter. Is there a reason to believe that there has been a change in the average height of male EDA students under Engr. Ventura if a random sample of 50 males in the present EDA class has an average height of 1.652 meters? Assume the standard deviation remains the same.
10. A recent medical study reported that blood pressure (diastolic type) for males in the 20 to 29 years-old range is approximately normally distributed with an mean of 91.7 and a standard deviation of 10.5. Using these numbers: a. What is the proportion of males in this age range with blood pressure greater than 100? b. What is proportion of males in this age range with blood pressure that is between 80 and 100? c. What are the Q1 and Q3 values?
Use the bootstrap distributions in Figure 1 to estimate the value of the sample statistic and standard error, and then use this information to give a 95 % confidence interval. In addition, give notation for the parameter being estimated. The bootstrap distribution in Figure 1, generated for a sample correlation to 0.25 0.30 0.35 0.40 0.45 0.50 0.55 Figure 1 Bootstrap distribution (a) Give the sample statistic for the parameter being estimated. Round your answer to one decimal place. Sample statistic = eTextbook and Media (b) Estimate the standard error. Round your answer to two decimal places. standard error = i eTextbook and Media (c) Give the 95 % confidence interval. Round your answers to two decimal places, if necessary. The 95 % confidence interval is i to i e Textbook and Media

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