1. Please correct all compile errors in the following declaration statements This program demonstrates the relationship between variables, addresses, and pointers. * / include int main (void) { * / / * int x[5] Declare and initialize variables. {1,2,3,4,5}; %3D Int *ptr=&x[0]; / * * / %p \n",x[0], &x[0] Print the variable and pointer contents. printf("x[0] ptr printf("After ptr printf("ptr* %d; address of x[0] %3D ptr + 1; ptr + 1 ******** \n"); %3D = %d; address of ptr %p \n",ptr,ptr); ptr++; printf("After ptr++ printf("ptr* ******** %d; address of ptr %p \n",*ptr,ptr); /* Exit program. * / return; }

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Question
```c
1. Please correct all compile errors in the following declaration statements

/*
    This program demonstrates the relationship between
    variables, addresses, and pointers.
*/
#include <stdio.h>
int main(void)
{

    /* Declare and initialize variables. */
    int x[5] = {1,2,3,4,5};
    int *ptr = &x[0];

    /* Print the variable and pointer contents. */
    printf("x[0] = %d;  address of x[0] = %p \n", x[0], &x[0]);

    ptr = ptr + 1;
    printf("After ptr = ptr + 1 ********\n");
    printf("ptr* = %d;  address of ptr = %p \n", *ptr, ptr);

    ptr++;
    printf("After ptr++  ********\n");
    printf("ptr* = %d;  address of ptr = %p \n", *ptr, ptr);

    /* Exit program. */
    return 0;

}
```

### Explanation of the Code

This C program demonstrates basic pointer operations. 

1. It starts by declaring an array `x` with five integers.
2. A pointer `ptr` is initialized to point to the first element of the array `x`.
3. It prints the value and address of `x[0]`.
   
   - **x[0] = %d:** This will print the integer value stored at `x[0]`.
   - **address of x[0] = %p:** This will print the memory address of `x[0]`.

4. The pointer `ptr` is incremented first by adding 1, and then using post-increment (`ptr++`), to point to subsequent elements of `x`.

   - After each increment, it prints:
     - **ptr* = %d:** The value at the new location `ptr` points to.
     - **address of ptr = %p:** The address stored in the `ptr`.

### Compile Errors

- The keyword `Int` should be `int` (case-sensitive).
- The `return;` statement should correctly be `return 0;`, indicating successful termination of `main`.
Transcribed Image Text:```c 1. Please correct all compile errors in the following declaration statements /* This program demonstrates the relationship between variables, addresses, and pointers. */ #include <stdio.h> int main(void) { /* Declare and initialize variables. */ int x[5] = {1,2,3,4,5}; int *ptr = &x[0]; /* Print the variable and pointer contents. */ printf("x[0] = %d; address of x[0] = %p \n", x[0], &x[0]); ptr = ptr + 1; printf("After ptr = ptr + 1 ********\n"); printf("ptr* = %d; address of ptr = %p \n", *ptr, ptr); ptr++; printf("After ptr++ ********\n"); printf("ptr* = %d; address of ptr = %p \n", *ptr, ptr); /* Exit program. */ return 0; } ``` ### Explanation of the Code This C program demonstrates basic pointer operations. 1. It starts by declaring an array `x` with five integers. 2. A pointer `ptr` is initialized to point to the first element of the array `x`. 3. It prints the value and address of `x[0]`. - **x[0] = %d:** This will print the integer value stored at `x[0]`. - **address of x[0] = %p:** This will print the memory address of `x[0]`. 4. The pointer `ptr` is incremented first by adding 1, and then using post-increment (`ptr++`), to point to subsequent elements of `x`. - After each increment, it prints: - **ptr* = %d:** The value at the new location `ptr` points to. - **address of ptr = %p:** The address stored in the `ptr`. ### Compile Errors - The keyword `Int` should be `int` (case-sensitive). - The `return;` statement should correctly be `return 0;`, indicating successful termination of `main`.
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Here in the given code, x is an array of integers while ptr is integer pointer. 

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