1. make me one question on relative motion in the forum with complete solutions. here is my example below of what I am expecting you to answer: NOTE: Don't copy the question below make me a similar question and then solve it as you see below how they solved it. Manny is playing golf with his friend, he hits the golf ball from a 7.0m high building with a velocity of 8.0 m/s [45° above the horizontal], and it lands next to a pond. How long does it take for the golf ball to hit the ground and reach the pond? vix viy (8.0m/s) cos 45 vix 5.65m/s (right) cos 45 = vix = sin 45 = viy vr viy- (8.0m/s) sin 45 viy = 5.65m/s (up (up) a = 9.81m/s² viy = 5.65m/s (up) s (up) Ad=7.0m (down) vfy² = viy² + 2a A dy vfy² = ((5.65m/s)²) + 2(−9.81m/s²)(–7. vfy=√169.2625 vfy = ±13m/s vfy = -13m/s vf=vi+a At – 13m/s = 5.65m/s + (−9.81m/s²) At -18.65m/s -9.81m/s² At= At = 1.9s -7.0m

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1. make me one question on relative motion in the forum with complete solutions.
here is my example below of what I am expecting you to answer:
NOTE: Don't copy the question below make me a similar question and then solve it as you see below how they solved it.
Manny is playing golf with his friend, he hits the golf ball from a 7.0m high
building with a velocity of 8.0 m/s [45° above the horizontal], and it lands next to
a pond. How long does it take for the golf ball to hit the ground and reach the
pond?
cos 45
vix
viy
vix =
(8.0m/s) cos 45
vix = 5.65m/s (right)
viy
vr
viy - (8.0m/s) sin 45
5.65m/s (up)
sin 45
viy
=
=
a = 9.81m/s²
viy
1= 5.65m/s (up)
Ad 7.0m (down
vfy² = viy² + 2a A dy
vfy² = ((5.65m/s) ²) + 2(-9.8
+2(-9.81m/s²
vfy=√169.2625
vfy = ±13m/s
vfy = -13m/s
vf=vi+a At
– 13m/s = 5.65m/s + (−–9.81m/s²) A t
-18.65m/s
-9.81m/s²
1/ 3²) (-7.
At=
At = 1.9s
-7.0m
Transcribed Image Text:1. make me one question on relative motion in the forum with complete solutions. here is my example below of what I am expecting you to answer: NOTE: Don't copy the question below make me a similar question and then solve it as you see below how they solved it. Manny is playing golf with his friend, he hits the golf ball from a 7.0m high building with a velocity of 8.0 m/s [45° above the horizontal], and it lands next to a pond. How long does it take for the golf ball to hit the ground and reach the pond? cos 45 vix viy vix = (8.0m/s) cos 45 vix = 5.65m/s (right) viy vr viy - (8.0m/s) sin 45 5.65m/s (up) sin 45 viy = = a = 9.81m/s² viy 1= 5.65m/s (up) Ad 7.0m (down vfy² = viy² + 2a A dy vfy² = ((5.65m/s) ²) + 2(-9.8 +2(-9.81m/s² vfy=√169.2625 vfy = ±13m/s vfy = -13m/s vf=vi+a At – 13m/s = 5.65m/s + (−–9.81m/s²) A t -18.65m/s -9.81m/s² 1/ 3²) (-7. At= At = 1.9s -7.0m
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