1. m m= 200g, k= 4.44 N/m, v[0) = 0.1 m/s to the right, x(0) = 0.05m to the left of the equilibrium position a. Derive the particular equation of motion of the mass m b. Solve for the position of the mass at t= 0.1s, t= 0.5s and t = 1s c. Draw a graph of x(t) from t= Os to t=1.5%, clearly showing the amplitude value, correct frequency, and initial conditions.
1. m m= 200g, k= 4.44 N/m, v[0) = 0.1 m/s to the right, x(0) = 0.05m to the left of the equilibrium position a. Derive the particular equation of motion of the mass m b. Solve for the position of the mass at t= 0.1s, t= 0.5s and t = 1s c. Draw a graph of x(t) from t= Os to t=1.5%, clearly showing the amplitude value, correct frequency, and initial conditions.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![1.
m
m= 200g, k= 4.44 N/m, v[0) = 0.1 m/s to the right, x(0) = 0.05m to the left of the equilibrium position
a. Derive the particular equation of motion of the mass m
b. Solve for the position of the mass at t= 0.1s, t= 0.5s and t = 1s
c. Draw a graph of x(t) from t= Os to t=1.5%, clearly showing the amplitude value, correct
frequency, and initial conditions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0b0b0b10-b7df-4299-9b93-f2e7f3b7207d%2Fbf130344-fb2d-4e25-9864-c11b8a95611c%2Fig5slgj_processed.png&w=3840&q=75)
Transcribed Image Text:1.
m
m= 200g, k= 4.44 N/m, v[0) = 0.1 m/s to the right, x(0) = 0.05m to the left of the equilibrium position
a. Derive the particular equation of motion of the mass m
b. Solve for the position of the mass at t= 0.1s, t= 0.5s and t = 1s
c. Draw a graph of x(t) from t= Os to t=1.5%, clearly showing the amplitude value, correct
frequency, and initial conditions.
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