2m 144 m, m. K₂ 77777 d₂ None of them m₂ K₂ © K₂ = ½ ((d₁)² + (d₂)²) K₂ = 1/2 (did₂) ² I'm For the robot above, please determine K2 (the kinetic energy of Link #2) = 1/(di + d₂) ² t 03 di, d₂ and ₂ are the joint variables m₂ = m₁ = m₂ = m₂ = 1 kg The moment of inertia of the last link is 3 kg. m². The mass centers are located on the middle point of each link.
2m 144 m, m. K₂ 77777 d₂ None of them m₂ K₂ © K₂ = ½ ((d₁)² + (d₂)²) K₂ = 1/2 (did₂) ² I'm For the robot above, please determine K2 (the kinetic energy of Link #2) = 1/(di + d₂) ² t 03 di, d₂ and ₂ are the joint variables m₂ = m₁ = m₂ = m₂ = 1 kg The moment of inertia of the last link is 3 kg. m². The mass centers are located on the middle point of each link.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
P1
![d₁
2m
K₂
m.
m₂
m,
77777
dz
None of them
Im
K₂ = ²/2 (d₁ + d₂) ²
M3
For the robot above, please determine K2 (the kinetic energy of Link #2)
K₂ = 1/2 (1₂) ²
K₂ = 1/((di)² + (d₂)²)
= 1/2 (did₂) ²
di, d₂ and O₂ are the
joint variables
m₂ = m₁ = m₂ = m₂ = 1 kg
The moment of inertia of
the last link is 3 kg. m².
The mass centers are located
on the middle point of each link.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F604b209b-079c-4a10-9152-9c7babe8a20c%2Ff83a5d33-234c-4233-9bf7-773db86b1f7d%2Fx0dpiy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:d₁
2m
K₂
m.
m₂
m,
77777
dz
None of them
Im
K₂ = ²/2 (d₁ + d₂) ²
M3
For the robot above, please determine K2 (the kinetic energy of Link #2)
K₂ = 1/2 (1₂) ²
K₂ = 1/((di)² + (d₂)²)
= 1/2 (did₂) ²
di, d₂ and O₂ are the
joint variables
m₂ = m₁ = m₂ = m₂ = 1 kg
The moment of inertia of
the last link is 3 kg. m².
The mass centers are located
on the middle point of each link.
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