P1 d₁2mK₂m.m₂m,77777dzNone of themImK₂ = ²/2 (d₁ + d₂) ²M3For the robot above, please determine K2 (the kinetic energy of Link #2)K₂ = 1/2 (1₂) ²K₂ = 1/((di)² + (d₂)²)= 1/2 (did₂) ²di, d₂ and O₂ are thejoint variablesm₂ = m₁ = m₂ = m₂ = 1 kgThe moment of inertia ofthe last link is 3 kg. m².The mass centers are locatedon the middle point of each link.

Answered: Image /qna-images/answer/f83a5d33-234c-4233-9bf7-773db86b1f7d.jpg

2m 144 m, m. K₂ 77777 d₂ None of them m₂ K₂ © K₂ = ½ ((d₁)² + (d₂)²) K₂ = 1/2 (did₂) ² I'm For the robot above, please determine K2 (the kinetic energy of Link #2) = 1/(di + d₂) ² t 03 di, d₂ and ₂ are the joint variables m₂ = m₁ = m₂ = m₂ = 1 kg The moment of inertia of the last link is 3 kg. m². The mass centers are located on the middle point of each link.

2m 144 m, m. K₂ 77777 d₂ None of them m₂ K₂ © K₂ = ½ ((d₁)² + (d₂)²) K₂ = 1/2 (did₂) ² I'm For the robot above, please determine K2 (the kinetic energy of Link #2) = 1/(di + d₂) ² t 03 di, d₂ and ₂ are the joint variables m₂ = m₁ = m₂ = m₂ = 1 kg The moment of inertia of the last link is 3 kg. m². The mass centers are located on the middle point of each link.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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