P1 d₁2mK₂m.m₂m,77777dzNone of themImK₂ = ²/2 (d₁ + d₂) ²M3For the robot above, please determine K2 (the kinetic energy of Link #2)K₂ = 1/2 (1₂) ²K₂ = 1/((di)² + (d₂)²)= 1/2 (did₂) ²di, d₂ and O₂ are thejoint variablesm₂ = m₁ = m₂ = m₂ = 1 kgThe moment of inertia ofthe last link is 3 kg. m².The mass centers are locatedon the middle point of each link.

Answered: Image /qna-images/answer/f83a5d33-234c-4233-9bf7-773db86b1f7d.jpg

2m 144 m, m. K₂ 77777 d₂ None of them m₂ K₂ © K₂ = ½ ((d₁)² + (d₂)²) K₂ = 1/2 (did₂) ² I'm For the robot above, please determine K2 (the kinetic energy of Link #2) = 1/(di + d₂) ² t 03 di, d₂ and ₂ are the joint variables m₂ = m₁ = m₂ = m₂ = 1 kg The moment of inertia of the last link is 3 kg. m². The mass centers are located on the middle point of each link.

2m 144 m, m. K₂ 77777 d₂ None of them m₂ K₂ © K₂ = ½ ((d₁)² + (d₂)²) K₂ = 1/2 (did₂) ² I'm For the robot above, please determine K2 (the kinetic energy of Link #2) = 1/(di + d₂) ² t 03 di, d₂ and ₂ are the joint variables m₂ = m₁ = m₂ = m₂ = 1 kg The moment of inertia of the last link is 3 kg. m². The mass centers are located on the middle point of each link.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Strain energy

The term strain indicates the variation in an object's length, area, and volume when the object is subjected to an external force. The external force may be of normal, shear, moment, torque, etc. The strain in an object depends on the types of external force and cross-section of the object. Mathematically, the evaluation of strain can be obtained with the help of elastic constants.

Question

d₁
2m
K₂
m.
m₂
m,
77777
dz
None of them
Im
K₂ = ²/2 (d₁ + d₂) ²
M3
For the robot above, please determine K2 (the kinetic energy of Link #2)
K₂ = 1/2 (1₂) ²
K₂ = 1/((di)² + (d₂)²)
= 1/2 (did₂) ²
di, d₂ and O₂ are the
joint variables
m₂ = m₁ = m₂ = m₂ = 1 kg
The moment of inertia of
the last link is 3 kg. m².
The mass centers are located
on the middle point of each link.

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