The transformation of position from polar to Cartesian coordinates is given by: x=rcose y=rsin 0 Determine the following 1. If a particle is moving in the plane with a velocity given by i and what is x and y? (Hint: differentiate the above equations to obtain expressions x = fi(r, 0,r, 0) and y = f₂(r, 0,r, 0). Make sure you use the product and chain rules!) 2. If a particle is moving in the plane with a velocity and acceleration given by r, è, i and what is and y? (Hint: differentiate the equation you obtained in Part 1 above to obtain expressions = f3(r,0,r,ė,ï,ö) and ÿ = f4(r,0,r,,,0). Partial solution: i = Ï sin 0 + 2r0 cos 0 + re cos 0 - r0² sin 0.)
The transformation of position from polar to Cartesian coordinates is given by: x=rcose y=rsin 0 Determine the following 1. If a particle is moving in the plane with a velocity given by i and what is x and y? (Hint: differentiate the above equations to obtain expressions x = fi(r, 0,r, 0) and y = f₂(r, 0,r, 0). Make sure you use the product and chain rules!) 2. If a particle is moving in the plane with a velocity and acceleration given by r, è, i and what is and y? (Hint: differentiate the equation you obtained in Part 1 above to obtain expressions = f3(r,0,r,ė,ï,ö) and ÿ = f4(r,0,r,,,0). Partial solution: i = Ï sin 0 + 2r0 cos 0 + re cos 0 - r0² sin 0.)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The transformation of position from polar to Cartesian coordinates is given by:
x = r cose
y=rsin 0
Determine the following
1. If a particle is moving in the plane with a velocity given by i and what is x and y? (Hint:
differentiate the above equations to obtain expressions x = f₁(r, 0,r,ė) and y = f₂(r,0,r,ė).
Make sure you use the product and chain rules!)
2. If a particle is moving in the plane with a velocity and acceleration given by †, 0, † and
what is * and y? (Hint: differentiate the equation you obtained in Part 1 above to obtain
expressions x = f(r,0,ƒ‚Ö‚Ï‚Ö) and ÿj = f(r,0,r,,,Ö). Partial solution: ÿj = sin 0 +
2r0 cos 0 + re cos 0 - r0² sin 0.)
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