1. Indicate the geometry of each carbon atom (i.e., linear, trigonal planar, tetrahedral) H :O: HH 1 S²N=3+0=3 Z 959 C C₁ T H H H 3+0=3 - trigonal = 3+0=3 = 4+0=4 = 4+0=4 = 4+0=4 2 = 4+0=4 = 4+0=4 - tetrahedral H H BH TH CH H 2. Use hybridization and orbitals to explain why some bonds above rotate freely and other bonds do not. Feel free to draw to explain your answer H → Sp² hybridization → Sp2-hybridization (trigonal) hybridization C3Sp2- C4 SP3 -hybridization Cz→ SP³ -hybridization Cos S.N=no. of bond + no. of won ar Lone POL Cs→Sp3-hybridization tetrahedral Cu→Sp3-hybridization G→Sp³-hybridization
1. Indicate the geometry of each carbon atom (i.e., linear, trigonal planar, tetrahedral) H :O: HH 1 S²N=3+0=3 Z 959 C C₁ T H H H 3+0=3 - trigonal = 3+0=3 = 4+0=4 = 4+0=4 = 4+0=4 2 = 4+0=4 = 4+0=4 - tetrahedral H H BH TH CH H 2. Use hybridization and orbitals to explain why some bonds above rotate freely and other bonds do not. Feel free to draw to explain your answer H → Sp² hybridization → Sp2-hybridization (trigonal) hybridization C3Sp2- C4 SP3 -hybridization Cz→ SP³ -hybridization Cos S.N=no. of bond + no. of won ar Lone POL Cs→Sp3-hybridization tetrahedral Cu→Sp3-hybridization G→Sp³-hybridization
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Bond Parameters
Many factors decide the covalent bonding between atoms. Some of the bond parameters are bond angle, bond order, enthalpy, bond length, etc. These parameters decide what kind of bond will form in atoms. Hence it is crucial to understand these parameters in detail and understand how changing these parameters affects the kind of bonding or various characteristics.
Bond Dissociation Energy
The tendency of an atom to attract an electron is known as its electronegativity.
Question
Please explain no. 2 in deyail
![1. Indicate the geometry of each carbon atom (i.e., linear, trigonal planar, tetrahedral).
디
C₁ S₁N=3+0=3
= 3+0=3
= 3+0=3
64 C = 4+0=4
=4+0=4
مرين
сз
H
8
HI
Н
H H:O:
H9
H H
-trigonal
tetrahedral
H
HO?
hybridization
C3-> Sp2-
C4 SP3 -hybridization
6H
&H
HOT H
H₁
I I
C₁ → Sp² hybridization
C₂ Sp²-hybridization trig
= 4+0=4
= 4+0=4
= 4+0=4
2. Use hybridization and orbitals to explain why some bonds above rotate freely and other
bonds do not. Feel free to draw to explain your answer
S.N=no. of bond
+ no. of
Lone
Pair
Cs→Sp3-hybridization tetrahedral
C-Sp3-hybridization
G→SP³-hybridization.
Cg → SP3 -hybridization
8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d929fa4-2fdc-40c7-801d-1fbf9b4298bd%2F6d57b954-8049-487c-a37a-7ad917981e6a%2F1k6qr7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Indicate the geometry of each carbon atom (i.e., linear, trigonal planar, tetrahedral).
디
C₁ S₁N=3+0=3
= 3+0=3
= 3+0=3
64 C = 4+0=4
=4+0=4
مرين
сз
H
8
HI
Н
H H:O:
H9
H H
-trigonal
tetrahedral
H
HO?
hybridization
C3-> Sp2-
C4 SP3 -hybridization
6H
&H
HOT H
H₁
I I
C₁ → Sp² hybridization
C₂ Sp²-hybridization trig
= 4+0=4
= 4+0=4
= 4+0=4
2. Use hybridization and orbitals to explain why some bonds above rotate freely and other
bonds do not. Feel free to draw to explain your answer
S.N=no. of bond
+ no. of
Lone
Pair
Cs→Sp3-hybridization tetrahedral
C-Sp3-hybridization
G→SP³-hybridization.
Cg → SP3 -hybridization
8
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