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1. In the presence of excess water (H2O), suppose a plant consumes 37.8 grams of CO2 during the week. Determine how many grams of glucose (C6H12O6) would be produced by the plant during this one-week period. The unbalanced chemical equation for the reaction is as follows: CO2g) + H2O) → CH12O6 (s) + O2() Vnoloso h ot blot oo d babuborq ai T 2. Based on the reaction below it was found that AgNO3(aq) is the limiting reactant if 2.00 g of Zn(s) and 2.50 g of AgNO3(aq) are combined. The amount of Zn(NO3)2(aq) recovered at the end of the reaction was 1.12 g. What is the percent yield of Zn(NO3)2(aq)? Zne) + AGNO3(aq) → Ags) + Zn(NO3)2(aq)

1. In the presence of excess water (H2O), suppose a plant consumes 37.8 grams of CO2 during the week. Determine how many grams of glucose (C6H12O6) would be produced by the plant during this one-week period. The unbalanced chemical equation for the reaction is as follows: CO2g) + H2O) → CH12O6 (s) + O2() Vnoloso h ot blot oo d babuborq ai T 2. Based on the reaction below it was found that AgNO3(aq) is the limiting reactant if 2.00 g of Zn(s) and 2.50 g of AgNO3(aq) are combined. The amount of Zn(NO3)2(aq) recovered at the end of the reaction was 1.12 g. What is the percent yield of Zn(NO3)2(aq)? Zne) + AGNO3(aq) → Ags) + Zn(NO3)2(aq)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please do both , if u hv plan to do only 1 then skip lets some other do all plz , again telling do all 

Do with step by step explanation, do not miss any point i will upvote

1. In the presence of excess water (H2O), suppose a plant consumes 37.8 grams of CO2 during the week. Determine how many grams of glucose (C6H1206) would be produced by the plant during this one-week period. The unbalanced chemical equation for the reaction is as follows: CO2e) + H2O) → C6H12O6 (s) + O2g) Tnodosot aih ot bloi fooe biay toeotay Ins bloiy Jeslonos imil or s 2. Based on the reaction below it was found that AgN03(aq) is the limiting reactant if 2.00 g of Zn(s) and 2.50 g of AgNO3(aq) are combined. The amount of Zn(NO3)2(aq) recovered at the end of the reaction was 1.12 g. What is the percent yield of Zn(NO3)2(aq)? Zns) + AGNO3(aq) → Ag) + Zn(NO3)2(aq)
Transcribed Image Text:1. In the presence of excess water (H2O), suppose a plant consumes 37.8 grams of CO2 during the week. Determine how many grams of glucose (C6H1206) would be produced by the plant during this one-week period. The unbalanced chemical equation for the reaction is as follows: CO2e) + H2O) → C6H12O6 (s) + O2g) Tnodosot aih ot bloi fooe biay toeotay Ins bloiy Jeslonos imil or s 2. Based on the reaction below it was found that AgN03(aq) is the limiting reactant if 2.00 g of Zn(s) and 2.50 g of AgNO3(aq) are combined. The amount of Zn(NO3)2(aq) recovered at the end of the reaction was 1.12 g. What is the percent yield of Zn(NO3)2(aq)? Zns) + AGNO3(aq) → Ag) + Zn(NO3)2(aq)
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