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1. In the given picture below, Alice throws the ball to the +X direction with an initial velocity 10m/s. Time elapsed during the motion is 5s, calculate the height that object is thrown and Vy component of the velocity after it hits the ground.

1. In the given picture below, Alice throws the ball to the +X direction with an initial velocity 10m/s. Time elapsed during the motion is 5s, calculate the height that object is thrown and Vy component of the velocity after it hits the ground.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please use the formulas in the second picture. 

Please write known and unknown like y = ?, x = ?, etc. too and show work in an easy to understand way.

 

 

**Projectile Motion, Constant Acceleration Formulas** **X Components (Horizontal):** - \( v_x = v_{x0} + a_x t \) - \( x = x_0 + v_{x0} t + \frac{1}{2} a_x t^2 \) - \( v_x^2 = v_{x0}^2 + 2a_x (x - x_0) \) **Projectile (Horizontal):** - \( v_x = v_{x0} \) - \( x = x_0 + v_{x0} t \) - \( v_x^2 = v_{x0}^2 \) --- **Y Components (Vertical):** - \( v_y = v_{y0} + a_y t \) - \( y = y_0 + v_{y0} t + \frac{1}{2} a_y t^2 \) - \( v_y^2 = v_{y0}^2 + 2a_y (y - y_0) \) **Projectile (Vertical):** - \( v_y = v_{y0} - gt \) - \( y = y_0 + v_{y0} t - \frac{1}{2} gt^2 \) - \( v_y^2 = v_{y0}^2 - 2g (y - y_0) \)
Transcribed Image Text:**Projectile Motion, Constant Acceleration Formulas** **X Components (Horizontal):** - \( v_x = v_{x0} + a_x t \) - \( x = x_0 + v_{x0} t + \frac{1}{2} a_x t^2 \) - \( v_x^2 = v_{x0}^2 + 2a_x (x - x_0) \) **Projectile (Horizontal):** - \( v_x = v_{x0} \) - \( x = x_0 + v_{x0} t \) - \( v_x^2 = v_{x0}^2 \) --- **Y Components (Vertical):** - \( v_y = v_{y0} + a_y t \) - \( y = y_0 + v_{y0} t + \frac{1}{2} a_y t^2 \) - \( v_y^2 = v_{y0}^2 + 2a_y (y - y_0) \) **Projectile (Vertical):** - \( v_y = v_{y0} - gt \) - \( y = y_0 + v_{y0} t - \frac{1}{2} gt^2 \) - \( v_y^2 = v_{y0}^2 - 2g (y - y_0) \)
**Problem Statement:** 1. In the given picture, Alice throws the ball to the +X direction with an initial velocity of 10 m/s. The time elapsed during the motion is 5 seconds. Calculate the height from which the object is thrown and the Vy component of the velocity after it hits the ground. **Diagram Explanation:** - Alice is standing on the edge of a cliff and throws a ball horizontally. - The initial velocity of the ball is shown as a horizontal arrow labeled \( V = 10 \, \text{m/s} \). - The ball's trajectory is depicted as a curved path from the edge of the cliff to the ground. - A vertical distance marker labeled \( h = ? \) indicates the unknown height of the cliff. - The point where the ball hits the ground is labeled with \( t = 5s \). - The vertical component of the velocity at the impact point is labeled \( Vy = ? \). **Key Concepts:** - The horizontal motion and vertical motion are independent. - The initial vertical velocity (\( Vy_0 \)) is 0 m/s since the ball is thrown horizontally. - Use kinematic equations to solve for \( h \) and \( Vy \).
Transcribed Image Text:**Problem Statement:** 1. In the given picture, Alice throws the ball to the +X direction with an initial velocity of 10 m/s. The time elapsed during the motion is 5 seconds. Calculate the height from which the object is thrown and the Vy component of the velocity after it hits the ground. **Diagram Explanation:** - Alice is standing on the edge of a cliff and throws a ball horizontally. - The initial velocity of the ball is shown as a horizontal arrow labeled \( V = 10 \, \text{m/s} \). - The ball's trajectory is depicted as a curved path from the edge of the cliff to the ground. - A vertical distance marker labeled \( h = ? \) indicates the unknown height of the cliff. - The point where the ball hits the ground is labeled with \( t = 5s \). - The vertical component of the velocity at the impact point is labeled \( Vy = ? \). **Key Concepts:** - The horizontal motion and vertical motion are independent. - The initial vertical velocity (\( Vy_0 \)) is 0 m/s since the ball is thrown horizontally. - Use kinematic equations to solve for \( h \) and \( Vy \).
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