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1. In a Rankine cycle, steam enters the turbine at 2.5 MPa and condenser at 50 kPa, what is the thermal efficiency of the cycle? At 2.5 MPa: he = 2803.1 kl/kg S = 1.0910 h = 340.49 V = 0.0010300 Sg = 6.2575 kl/ kg – K S = 6.5029 htg = 2305.4 At 50 kPa: %3D

1. In a Rankine cycle, steam enters the turbine at 2.5 MPa and condenser at 50 kPa, what is the thermal efficiency of the cycle? At 2.5 MPa: he = 2803.1 kl/kg S = 1.0910 h = 340.49 V = 0.0010300 Sg = 6.2575 kl/ kg – K S = 6.5029 htg = 2305.4 At 50 kPa: %3D

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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1. In a Rankine cycle, steam enters the turbine at 2.5 MPa and condenser at 50 kPa, what is the thermal efficiency of the cycle? At 2.5 MPa: hg = 2803.1 kl/kg S = 1.0910 he = 340.49 V = 0.0010300 Sg = 6.2575 kJ/ kg – K Sig = 6.5029 hy = 2305.4 At 50 kPa: 2. In an ideal Rankine cycle, the steam throttle condition is 4.10O MPa and 440°C. If turbine exhaust is 0.105 MPa, determine the thermal efficiency of the cycle.
Transcribed Image Text:1. In a Rankine cycle, steam enters the turbine at 2.5 MPa and condenser at 50 kPa, what is the thermal efficiency of the cycle? At 2.5 MPa: hg = 2803.1 kl/kg S = 1.0910 he = 340.49 V = 0.0010300 Sg = 6.2575 kJ/ kg – K Sig = 6.5029 hy = 2305.4 At 50 kPa: 2. In an ideal Rankine cycle, the steam throttle condition is 4.10O MPa and 440°C. If turbine exhaust is 0.105 MPa, determine the thermal efficiency of the cycle.
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