PROGRAMMING LANGUAGE: C++Note: Kindly refer to the attached screenshot for the sample program.1. Identify the format of the function used: no return type & no parameter, with return type & no parameter, no return type & with parameter and with return type & with parameter.2. Identify the format and actual parameters.3. Identify the function signature4. Identify parameter if value parameter, reference parameter or constant reference parameter is used.5. Identify the the scope of variable used.6. Identify the type of C++ function is used. main.cpp+1 #include 2 #include 34 using namespace std;56 const double GALLONS_IN_A_CUBIC_FOOT = 7.48;8 double poolCapacity(double len, double wid, double dep);9 void poolFillTime(double len, double wid, double dep,1011 void print(int fTime);double fRate, int& fTime);1213 int main(().14 {15double length, width, depth;double fillRate;int fillTime;16171819cout <« fixed <« showpoint « setprecision(2);2021cout <« "Enter the length, width, and the depth of the "« "pool, (in feet): ";cin >> length >> width >> depth;222324cout <« endl;25cout <« "Enter the rate of the water, (in gallons per minute): ";cin >> fillRate;262728cout <« endl;29poolFillTime(length, width, depth, fillRate, fillTime);print(fillTime);30313233return 0;34 } 3536 double poolCapacity(double len, double wid, double dep)37 {38double volume;39double poolWaterCapacity;4041volume = len * wid * dep;42poolWaterCapacity = volume * GALLONS_IN_A_CUBIC_FOOT;4344return poolWaterCapacity;45 }4647 void poolFillTime(double len, double wid, double dep,48double fRate, int& fTime)49 {50double poolWaterCapacity;51poolWaterCapacity = poolCapacity(len, wid, dep);fTime = static_cast (poolWaterCapacity / fRate + 0.5);525354 }5556 void print(int ƒTime)57 {58cout <« "The time to fill the pool is approximately:<« fTime / 60 <« " hour(s) and " <« fTime % 60<« " minute(s)." <« endl;5960II61 }62

Using C++ Programming Language: 1. Identify the format of the function used: no return type & no…

Answered: 1. Identify the format of the function…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Question

PROGRAMMING LANGUAGE: C++

Note: Kindly refer to the attached screenshot for the sample program.

1. Identify the format of the function used: no return type & no parameter, with return type & no parameter, no return type & with parameter and with return type & with parameter.

2. Identify the format and actual parameters.

3. Identify the function signature

4. Identify parameter if value parameter, reference parameter or constant reference parameter is used.

5. Identify the the scope of variable used.

6. Identify the type of C++ function is used.

main.cpp
+
1 #include <iostream>
2 #include <iomanip>
3
4 using namespace std;
5
6 const double GALLONS_IN_A_CUBIC_FOOT = 7.48;
8 double poolCapacity(double len, double wid, double dep);
9 void poolFillTime(double len, double wid, double dep,
10
11 void print(int fTime);
double fRate, int& fTime);
12
13 int main(().
14 {
15
double length, width, depth;
double fillRate;
int fillTime;
16
17
18
19
cout <« fixed <« showpoint « setprecision(2);
20
21
cout <« "Enter the length, width, and the depth of the "
« "pool, (in feet): ";
cin >> length >> width >> depth;
22
23
24
cout <« endl;
25
cout <« "Enter the rate of the water, (in gallons per minute): ";
cin >> fillRate;
26
27
28
cout <« endl;
29
poolFillTime(length, width, depth, fillRate, fillTime);
print(fillTime);
30
31
32
33
return 0;
34 }

35
36 double poolCapacity(double len, double wid, double dep)
37 {
38
double volume;
39
double poolWaterCapacity;
40
41
volume = len * wid * dep;
42
poolWaterCapacity = volume * GALLONS_IN_A_CUBIC_FOOT;
43
44
return poolWaterCapacity;
45 }
46
47 void poolFillTime(double len, double wid, double dep,
48
double fRate, int& fTime)
49 {
50
double poolWaterCapacity;
51
poolWaterCapacity = poolCapacity(len, wid, dep);
fTime = static_cast<int> (poolWaterCapacity / fRate + 0.5);
52
53
54 }
55
56 void print(int ƒTime)
57 {
58
cout <« "The time to fill the pool is approximately:
<« fTime / 60 <« " hour(s) and " <« fTime % 60
<« " minute(s)." <« endl;
59
60
II
61 }
62

Expert Solution

Step by step

Solved in 2 steps with 7 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions