Please choose the correct answer. About feedback. 1. Identify the feedback topology being used.4. Determine the value of the feedback factor.Oshunt-ShuntО-0.4OSeries-Shunt0-666.667 µSOSeries-Series01Oshunt-Series01000 N5. Obtain the value for the open-loop gain.2. Calculate the value for the open-loop input resistance.0441.17647 S02812503125 NO-1785003035.71429 N07.5 S0500 NO-70312500 N6. What is the value of the closed-loop gain?3. Compute the value for the open-loop transconductance.083.3 S0999.86668 µSО-892.5 S01499.96800NO-35.7 S00.99996040 mSO-2.49965 Use the circuit shown to answer the following questions. Assume that the transistors are already biased in the desired regions of operation. Further assume thatthe capacitors have infinite capacitance so that they can be treated as shorts during small-signal analysis. Use the following parameters:Rs = 100 NRc = 15 kNRp = 83.3 kNRE =1 kNRF = 1.5 kRG1 = 5 kNRc2 =1 kNRc3 = 2.5 kN• RL = 5 kNVAQ1 → 0AM1 = 0 V-1• Im,M1 = 625 mSIm,Q1 = 40 mSBạ1 = 99RG1RpRcCLVoutRG3Vin oRLM1CGRG2RsC'sRECFRF

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Electrical Engineering

1. Identify the feedback topology being used. Oshunt-Shunt OSeries-Shunt OSeries-Series Oshunt-Series

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Please choose the correct answer. About feedback.

1. Identify the feedback topology being used.
4. Determine the value of the feedback factor.
Oshunt-Shunt
О-0.4
OSeries-Shunt
0-666.667 µS
OSeries-Series
01
Oshunt-Series
01000 N
5. Obtain the value for the open-loop gain.
2. Calculate the value for the open-loop input resistance.
0441.17647 S
028125
03125 N
O-17850
03035.71429 N
07.5 S
0500 N
O-70312500 N
6. What is the value of the closed-loop gain?
3. Compute the value for the open-loop transconductance.
083.3 S
0999.86668 µS
О-892.5 S
01499.96800N
O-35.7 S
00.99996
040 mS
O-2.49965

Use the circuit shown to answer the following questions. Assume that the transistors are already biased in the desired regions of operation. Further assume that
the capacitors have infinite capacitance so that they can be treated as shorts during small-signal analysis. Use the following parameters:
Rs = 100 N
Rc = 15 kN
Rp = 83.3 kN
RE =1 kN
RF = 1.5 k
RG1 = 5 kN
Rc2 =1 kN
Rc3 = 2.5 kN
• RL = 5 kN
VAQ1 → 0
AM1 = 0 V-1
• Im,M1 = 625 mS
Im,Q1 = 40 mS
Bạ1 = 99
RG1
Rp
Rc
CL
Vout
RG3
Vin o
RL
M1
CG
RG2
Rs
C's
RE
CF
RF

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