1. How many grams for silver chromate will precipitate when 100.0 mL of 0.400 M silver nitrate solution is added to potassium chromate? 2 AgNO3(aq) K₂CRO4(04) 2 KNO3(09) + Ag₂CrO4(0) +

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
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Problem 103IL: The cations Ba2+ and Sr2+ can be precipitated as very insoluble sulfates. (a) If you add sodium...
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Honors Chemistry Worksheet - Solution Stoichiometry
1. How many grams for silver chromate will precipitate when 100.0 mL of 0.400 M silver nitrate solution is added to potassium
chromate?
2 AgNO3(aq) + K₂CrO4(04)
2 KNO3(09) + Ag2CrO4(0)
2. If 30.0 mL of a 0.299 M sodium hydroxide solution are added to 50.0 mL of a 0.950 M cupric sulfate solution, what mass of
the precipitate will form? 2 NaOH(aq) +
CuSO4(09)
Cu(OH)2(g) + 2 Na2504(09)
ထ
3. What volume of 0.455 M silver nitrate solution is required to precipitate all of the bromide ions in 40.00 mL of a 0.120 M
strontium bromide solution?
Br (aq)
Ag* (aq) +
AgBr(s)
4. What volume of 2.50 M hydrobromic acid solution will be consumed in reacting with 30.00 g of aluminum metal?
2 Al(s) + 6 HBr(aq)
2 AlBr3(aq)
3 H2(g)
--->
Transcribed Image Text:Honors Chemistry Worksheet - Solution Stoichiometry 1. How many grams for silver chromate will precipitate when 100.0 mL of 0.400 M silver nitrate solution is added to potassium chromate? 2 AgNO3(aq) + K₂CrO4(04) 2 KNO3(09) + Ag2CrO4(0) 2. If 30.0 mL of a 0.299 M sodium hydroxide solution are added to 50.0 mL of a 0.950 M cupric sulfate solution, what mass of the precipitate will form? 2 NaOH(aq) + CuSO4(09) Cu(OH)2(g) + 2 Na2504(09) ထ 3. What volume of 0.455 M silver nitrate solution is required to precipitate all of the bromide ions in 40.00 mL of a 0.120 M strontium bromide solution? Br (aq) Ag* (aq) + AgBr(s) 4. What volume of 2.50 M hydrobromic acid solution will be consumed in reacting with 30.00 g of aluminum metal? 2 Al(s) + 6 HBr(aq) 2 AlBr3(aq) 3 H2(g) --->
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