1. For the following, put all final answers in the +20V table below or sketch a similar table. а. Solve for the equivalent resistance of 20 the circuit. Put your final answer in the table. 12 Q b. Solve for the voltage across and the 10 current through each resistor in the circuit. 50 20 Q Fill in the table. ww ww

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1. For the following, put all final answers in the table below or sketch a similar table.
   a. Solve for the equivalent resistance of the circuit. Put your final answer in the table.
   b. Solve for the voltage across and the current through each resistor in the circuit. Fill in the table.

The diagram shows a circuit with a 20V battery connected in series with a 1-ohm resistor. This series is in parallel with a combination of resistors: a 12-ohm resistor, and further parallel resistors of 2 ohms and a series combination of 5 ohm and 20 ohm resistors.

The table to fill in:
- Equivalent Resistance: ______ Ω
- Resistor (Ω): Voltage (V), Current (A)
  - 1 Ω: |ΔV| (V), |I| (A)
  - 2 Ω: |ΔV| (V), |I| (A)
  - 5 Ω: |ΔV| (V), |I| (A)
  - 12 Ω: |ΔV| (V), |I| (A)
  - 20 Ω: |ΔV| (V), |I| (A)
Transcribed Image Text:1. For the following, put all final answers in the table below or sketch a similar table. a. Solve for the equivalent resistance of the circuit. Put your final answer in the table. b. Solve for the voltage across and the current through each resistor in the circuit. Fill in the table. The diagram shows a circuit with a 20V battery connected in series with a 1-ohm resistor. This series is in parallel with a combination of resistors: a 12-ohm resistor, and further parallel resistors of 2 ohms and a series combination of 5 ohm and 20 ohm resistors. The table to fill in: - Equivalent Resistance: ______ Ω - Resistor (Ω): Voltage (V), Current (A) - 1 Ω: |ΔV| (V), |I| (A) - 2 Ω: |ΔV| (V), |I| (A) - 5 Ω: |ΔV| (V), |I| (A) - 12 Ω: |ΔV| (V), |I| (A) - 20 Ω: |ΔV| (V), |I| (A)
Expert Solution
Step 1

The battery voltage=+20 V

20 ohm and 5 ohm are connected in parallel1Rp1=120+15Rp1=20×520+5=4 ohmRp1 is connected in series with the 2 ohm resistor,Rs1=Rp1+2=4+2=6 ohmRs1 is connected in parallel to 12 ohm resistor1Rp=1Rs1+112=16+112Rp=12×612+6=4 ohm

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