1. Are R1 and lR2 connected in series or parallel? 2. If R1 = 5kN and R2 = 10k2, what will the equivalent resistance be? %3D 3. If the battery is a 12V battery, what will the current through the it be?
1. Are R1 and lR2 connected in series or parallel? 2. If R1 = 5kN and R2 = 10k2, what will the equivalent resistance be? %3D 3. If the battery is a 12V battery, what will the current through the it be?
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![### Circuit Analysis
The image shows a simple electrical circuit with two resistors, \( R_1 \) and \( R_2 \), connected to a voltage source \( V \).
1. **Question**: Are \( R_1 \) and \( R_2 \) connected in series or parallel?
- **Explanation**: The resistors are connected in series, as the same current flows through both resistors one after the other.
2. **Question**: If \( R_1 = 5 \, \text{k}\Omega \) and \( R_2 = 10 \, \text{k}\Omega \), what will the equivalent resistance be?
- **Calculation**: In a series circuit, the equivalent resistance \( R_{\text{eq}} \) is the sum of the individual resistances:
\[
R_{\text{eq}} = R_1 + R_2 = 5 \, \text{k}\Omega + 10 \, \text{k}\Omega = 15 \, \text{k}\Omega
\]
3. **Question**: If the battery is a 12V battery, what will the current through it be?
- **Calculation**: Using Ohm’s Law \( V = IR \), where \( V \) is the voltage, \( I \) is the current, and \( R \) is the resistance:
\[
I = \frac{V}{R_{\text{eq}}} = \frac{12 \, \text{V}}{15 \, \text{k}\Omega} = 0.8 \, \text{mA}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc11f26fd-cef8-49ce-a518-26ea804f3de8%2F274933a5-387c-4e81-ba29-666ef9d8657d%2Frnrzwna_processed.gif&w=3840&q=75)
Transcribed Image Text:### Circuit Analysis
The image shows a simple electrical circuit with two resistors, \( R_1 \) and \( R_2 \), connected to a voltage source \( V \).
1. **Question**: Are \( R_1 \) and \( R_2 \) connected in series or parallel?
- **Explanation**: The resistors are connected in series, as the same current flows through both resistors one after the other.
2. **Question**: If \( R_1 = 5 \, \text{k}\Omega \) and \( R_2 = 10 \, \text{k}\Omega \), what will the equivalent resistance be?
- **Calculation**: In a series circuit, the equivalent resistance \( R_{\text{eq}} \) is the sum of the individual resistances:
\[
R_{\text{eq}} = R_1 + R_2 = 5 \, \text{k}\Omega + 10 \, \text{k}\Omega = 15 \, \text{k}\Omega
\]
3. **Question**: If the battery is a 12V battery, what will the current through it be?
- **Calculation**: Using Ohm’s Law \( V = IR \), where \( V \) is the voltage, \( I \) is the current, and \( R \) is the resistance:
\[
I = \frac{V}{R_{\text{eq}}} = \frac{12 \, \text{V}}{15 \, \text{k}\Omega} = 0.8 \, \text{mA}
\]
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