1. For the diagram shown k = 250N/m for the spring, m¡ = 8.0kg, 0 = 30° and %3D %3D 8.0kg. Draw free body diagrams for each mass, label each force, m determine their values and determine how much the spring is stretched when the system is in equilibrium. 2 =

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Chapter1: Units, Trigonometry. And Vectors
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Please help me answer this problem and thoroughly explain the formulas behind each step, especially those relating to the spring and equilibrium. Thank you!

 

### Problem Statement:

1. For the diagram shown, \( k = 250 \text{N/m} \) for the spring, \( m_1 = 8.0 \text{kg} \), \( \theta = 30^\circ \) and \( m_2 = 8.0 \text{kg} \). Draw free body diagrams for each mass, label each force, determine their values and determine how much the spring is stretched when the system is in equilibrium.

### Diagram Analysis:

The diagram depicts a system consisting of:

- A block \( m_1 \) on an inclined plane at an angle \( \theta \).
- A spring with spring constant \( k \) attached to block \( m_1 \).
- A pulley system with a hanging block \( m_2 \).

### Instructions for Solving the Problem:

1. **Draw Free Body Diagrams (FBD):**

   - **For \( m_1 \)**:
     - Weight (\( W_1 \)): \( W_1 = m_1 g \)
     - Normal force (\( N \)) perpendicular to the inclined plane.
     - Spring force (\( F_s \)) acting along the plane.
     - Friction force (if applicable).
     - Gravitational component parallel (\( W_{1x} = m_1 g \sin \theta \)) and perpendicular to the plane (\( W_{1y} = m_1 g \cos \theta \)).

   - **For \( m_2 \)**:
     - Weight (\( W_2 \)): \( W_2 = m_2 g \)
     - Tension (\( T \)) in the string connected to \( m_2 \).

2. **Force Equations:**

   - For \( m_1 \) on the inclined plane:
     - Along the plane: \( F_s = m_1 g \sin \theta \)
     - Perpendicular to the plane: \( N = m_1 g \cos \theta \)

   - For \( m_2 \) (since the system is in equilibrium):
     - \( T = m_2 g \)

3. **Spring Force Calculation:**

   Since the system is in equilibrium:
   \[
   m_1 g \sin \theta = k \Delta x
   \]

   Where:
   - \( \Delta x \) is
Transcribed Image Text:### Problem Statement: 1. For the diagram shown, \( k = 250 \text{N/m} \) for the spring, \( m_1 = 8.0 \text{kg} \), \( \theta = 30^\circ \) and \( m_2 = 8.0 \text{kg} \). Draw free body diagrams for each mass, label each force, determine their values and determine how much the spring is stretched when the system is in equilibrium. ### Diagram Analysis: The diagram depicts a system consisting of: - A block \( m_1 \) on an inclined plane at an angle \( \theta \). - A spring with spring constant \( k \) attached to block \( m_1 \). - A pulley system with a hanging block \( m_2 \). ### Instructions for Solving the Problem: 1. **Draw Free Body Diagrams (FBD):** - **For \( m_1 \)**: - Weight (\( W_1 \)): \( W_1 = m_1 g \) - Normal force (\( N \)) perpendicular to the inclined plane. - Spring force (\( F_s \)) acting along the plane. - Friction force (if applicable). - Gravitational component parallel (\( W_{1x} = m_1 g \sin \theta \)) and perpendicular to the plane (\( W_{1y} = m_1 g \cos \theta \)). - **For \( m_2 \)**: - Weight (\( W_2 \)): \( W_2 = m_2 g \) - Tension (\( T \)) in the string connected to \( m_2 \). 2. **Force Equations:** - For \( m_1 \) on the inclined plane: - Along the plane: \( F_s = m_1 g \sin \theta \) - Perpendicular to the plane: \( N = m_1 g \cos \theta \) - For \( m_2 \) (since the system is in equilibrium): - \( T = m_2 g \) 3. **Spring Force Calculation:** Since the system is in equilibrium: \[ m_1 g \sin \theta = k \Delta x \] Where: - \( \Delta x \) is
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