pearson.com x + Part A A partridge of mass 4.99 kg is suspended from a pear tree by an ideal spring of negligible mass. When the partridge is pulled down 0.100 m below its equilibrium position and released, it vibrates with a period of 4.17 s. What is its speed as it passes through the equilibrium position? ΑΣΦ 00 5 T 16 40 6 Y G H v = Submit Request Answer Part B G ? m/s 0 > Review | Constants What is its acceleration when it is 0.050 m above the equilibrium position? a = ■% ΑΣΦ Submit Part C Q Search hp & 1 U 4+ 00 T 19 144 10 <-11 ( 9 Request Answer L M 144 112 ? m/s² 13 ارم 11:56 PM 5/7/2024 ins prt sc delete home end { O } P [ K L backspace. num lock t enter 7 home A Part C G When it is moving upward, how much time is required for it to move from a point 0.050 m below its equilibrium position to a point 0.050 m above it? t = Submit Part D ΤΟ ΑΣΦ Request Answer ? S The motion of the partridge is stopped, and then it is removed from the spring. How much does the spring shorten? ΜΕ ΑΣΦ |A|= ? m on Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | ㅁㅁ hp οι 112 } ] 2 P 11:56 PM 714 5/7/2024 infort sc delete home end pg up t backspace num lock 7 home 88 e + 9 pg up X pg dn
pearson.com x + Part A A partridge of mass 4.99 kg is suspended from a pear tree by an ideal spring of negligible mass. When the partridge is pulled down 0.100 m below its equilibrium position and released, it vibrates with a period of 4.17 s. What is its speed as it passes through the equilibrium position? ΑΣΦ 00 5 T 16 40 6 Y G H v = Submit Request Answer Part B G ? m/s 0 > Review | Constants What is its acceleration when it is 0.050 m above the equilibrium position? a = ■% ΑΣΦ Submit Part C Q Search hp & 1 U 4+ 00 T 19 144 10 <-11 ( 9 Request Answer L M 144 112 ? m/s² 13 ارم 11:56 PM 5/7/2024 ins prt sc delete home end { O } P [ K L backspace. num lock t enter 7 home A Part C G When it is moving upward, how much time is required for it to move from a point 0.050 m below its equilibrium position to a point 0.050 m above it? t = Submit Part D ΤΟ ΑΣΦ Request Answer ? S The motion of the partridge is stopped, and then it is removed from the spring. How much does the spring shorten? ΜΕ ΑΣΦ |A|= ? m on Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | ㅁㅁ hp οι 112 } ] 2 P 11:56 PM 714 5/7/2024 infort sc delete home end pg up t backspace num lock 7 home 88 e + 9 pg up X pg dn
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
Old hw, trying to review for exam, please show all steps
![pearson.com
x +
Part A
A partridge of mass 4.99 kg is suspended from a
pear tree by an ideal spring of negligible mass.
When the partridge is pulled down 0.100 m below
its equilibrium position and released, it vibrates with
a period of 4.17 s.
What is its speed as it passes through the equilibrium position?
ΑΣΦ
00
5
T
16
40
6
Y
G
H
v =
Submit
Request Answer
Part B
G
?
m/s
0 >
Review | Constants
What is its acceleration when it is 0.050 m above the equilibrium position?
a =
■%
ΑΣΦ
Submit
Part C
Q Search
hp
& 1
U
4+
00
T
19
144
10
<-11
(
9
Request Answer
L
M
144
112
?
m/s²
13
ارم
11:56 PM
5/7/2024
ins
prt sc
delete
home
end
{
O
}
P
[
K
L
backspace.
num
lock
t
enter
7
home
A](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92dd192b-2b85-4e23-91c3-a8e23aec13bb%2F92dea263-c7aa-4124-9dc2-0e26337dda47%2F65uw8ka_processed.jpeg&w=3840&q=75)
Transcribed Image Text:pearson.com
x +
Part A
A partridge of mass 4.99 kg is suspended from a
pear tree by an ideal spring of negligible mass.
When the partridge is pulled down 0.100 m below
its equilibrium position and released, it vibrates with
a period of 4.17 s.
What is its speed as it passes through the equilibrium position?
ΑΣΦ
00
5
T
16
40
6
Y
G
H
v =
Submit
Request Answer
Part B
G
?
m/s
0 >
Review | Constants
What is its acceleration when it is 0.050 m above the equilibrium position?
a =
■%
ΑΣΦ
Submit
Part C
Q Search
hp
& 1
U
4+
00
T
19
144
10
<-11
(
9
Request Answer
L
M
144
112
?
m/s²
13
ارم
11:56 PM
5/7/2024
ins
prt sc
delete
home
end
{
O
}
P
[
K
L
backspace.
num
lock
t
enter
7
home
A
![Part C
G
When it is moving upward, how much time is required for it to move from a point 0.050 m below
its equilibrium position to a point 0.050 m above it?
t =
Submit
Part D
ΤΟ ΑΣΦ
Request Answer
?
S
The motion of the partridge is stopped, and then it is removed from the spring. How much does
the spring shorten?
ΜΕ ΑΣΦ
|A|=
?
m
on Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us |
ㅁㅁ
hp
οι
112
}
]
2
P
11:56 PM
714
5/7/2024
infort sc
delete
home
end
pg up
t
backspace
num
lock
7
home
88
e
+
9
pg up
X
pg dn](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92dd192b-2b85-4e23-91c3-a8e23aec13bb%2F92dea263-c7aa-4124-9dc2-0e26337dda47%2Fh2y9m0e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part C
G
When it is moving upward, how much time is required for it to move from a point 0.050 m below
its equilibrium position to a point 0.050 m above it?
t =
Submit
Part D
ΤΟ ΑΣΦ
Request Answer
?
S
The motion of the partridge is stopped, and then it is removed from the spring. How much does
the spring shorten?
ΜΕ ΑΣΦ
|A|=
?
m
on Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us |
ㅁㅁ
hp
οι
112
}
]
2
P
11:56 PM
714
5/7/2024
infort sc
delete
home
end
pg up
t
backspace
num
lock
7
home
88
e
+
9
pg up
X
pg dn
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