11. (II) Particles of charge +65, +48, and -95 μC are placed in a line (Fig. 16-52). The center one is 0.35 m from each of the others. Calculate the net force on each charge due to the other two. +65 μC +48 μC -95 μµC 0.35 m 0.35 m FIGURE 16-52 Problem 11.
11. (II) Particles of charge +65, +48, and -95 μC are placed in a line (Fig. 16-52). The center one is 0.35 m from each of the others. Calculate the net force on each charge due to the other two. +65 μC +48 μC -95 μµC 0.35 m 0.35 m FIGURE 16-52 Problem 11.
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![## Example Problem on Coulomb's Law
**Problem Statement:**
**(II)** Particles of charge \(+65 \, \mu\text{C}\), \(+48 \, \mu\text{C}\), and \(-95 \, \mu\text{C}\) are placed in a line (Fig. 16–52). The center one is \(0.35 \, \text{m}\) from each of the others. Calculate the net force on each charge due to the other two.
### Diagram Description:
In **FIGURE 16-52 Problem 11**, three charged particles are aligned in a straight line. Here is the layout:
- A particle with a charge of \(+65 \, \mu\text{C}\) is placed on the left.
- A particle with a charge of \(+48 \, \mu\text{C}\) is placed in the middle.
- A particle with a charge of \(-95 \, \mu\text{C}\) is placed on the right.
The distance between \(+65 \, \mu\text{C}\) and \(+48 \, \mu\text{C}\) is \(0.35 \, \text{m}\). Similarly, the distance between \(+48 \, \mu\text{C}\) and \(-95 \, \mu\text{C}\) is also \(0.35 \, \text{m}\). The charges and distances are clearly depicted and labeled in the figure:
### Diagram:
```
+65 µC +48 µC -95 µC
● ---------●--------- ●
| 0.35 m | 0.35 m |
```
To understand the forces, recall Coulomb’s Law:
\[ F = k_e \frac{|q_1 q_2|}{r^2} \]
where \( k_e = 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \), \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between the charges. Apply this law calculating the forces between each pair of charges and then find the vector sum to get the net force on](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22536c29-fcc1-4871-92e0-85fb58db97f7%2F860a6e20-8b2f-48d0-9404-215529ee9ccd%2F69xktic_processed.png&w=3840&q=75)
Transcribed Image Text:## Example Problem on Coulomb's Law
**Problem Statement:**
**(II)** Particles of charge \(+65 \, \mu\text{C}\), \(+48 \, \mu\text{C}\), and \(-95 \, \mu\text{C}\) are placed in a line (Fig. 16–52). The center one is \(0.35 \, \text{m}\) from each of the others. Calculate the net force on each charge due to the other two.
### Diagram Description:
In **FIGURE 16-52 Problem 11**, three charged particles are aligned in a straight line. Here is the layout:
- A particle with a charge of \(+65 \, \mu\text{C}\) is placed on the left.
- A particle with a charge of \(+48 \, \mu\text{C}\) is placed in the middle.
- A particle with a charge of \(-95 \, \mu\text{C}\) is placed on the right.
The distance between \(+65 \, \mu\text{C}\) and \(+48 \, \mu\text{C}\) is \(0.35 \, \text{m}\). Similarly, the distance between \(+48 \, \mu\text{C}\) and \(-95 \, \mu\text{C}\) is also \(0.35 \, \text{m}\). The charges and distances are clearly depicted and labeled in the figure:
### Diagram:
```
+65 µC +48 µC -95 µC
● ---------●--------- ●
| 0.35 m | 0.35 m |
```
To understand the forces, recall Coulomb’s Law:
\[ F = k_e \frac{|q_1 q_2|}{r^2} \]
where \( k_e = 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \), \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between the charges. Apply this law calculating the forces between each pair of charges and then find the vector sum to get the net force on
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