2015E 104time ($)tim: (5)G. Two objects appear at the same place (15 cm) at 1 second, one disappears at 20 cm at 2 seconds whileanother appears at x = 0, both disappear at same location at 3 seconds. (Cannot reproduce withmotion sensor. Not a function.)H. Constant velocity of +2 cm/s, acceleration = zero, change in position = 10 cm.I.Constant acceleration+0.8 cm/s, initial velocity = 0 cm/s.3tine (5)time (s)tine (5)25.tina (s)Constant acceleration = -1 cm/s, initial velocity = +3 cm/s.tiae (5)J.K. Initial velocity = zero, acceleration is positive and increasing to about +1 cm/s/s.L. Initial velocity = zero. For first 2 seconds, acceleration =-2 cm/s, from 2-3 seconds, acceleration = +4cm/s; after t = 3 seconds, both velocity and acceleration are zero.%3DM. Acceleration is initially negative, changes to zero. Initial velocity = 4 cm/s, decreases to about -1.5cm/s.N. Initial velocity = 4 cm/s. Acceleration is initially negative, changes to zero by 3 seconds and remainszero. Final constant velocity = +1.5 cm/s.0. Initial velocity = -2 cm/s, is constant for first 2 seconds. Then there is a constant acceleration of+1.33 cm/s as velocity increases to 2 cm/s.() A3. 1. For each of the following graphs, discuss with your team and think of a motion that would create the graph.Be sure that you can accurately describe the velocity and acceleration for each motion.2. Your team will be assigned two motions. Write a detailed description of the motions, with enough detail sothat someone can follow your instructions and recreate the graph.201510time (s)A. Constant position = 5 cm from origin. Velocity = 0, acceleration = 0.B. Constant velocity = +2 cm/s, acceleration = 0, initial position = 5 cm.C. Constant velocity = -3 cm/s, acceleration 0, initial position = 20 cm.%3D201515E 10102112tim: (5)D. Velocity changes from 0 to +5 cm/s. Acceleration is positive, and constant (if the position vs. time curveis parabolic.) Initial position = 3 cm.E. Velocity and acceleration are both changing and alternating from positive to negative, initial position =10 cm, alternates from 15 cm to 5 cm.F. Starting from origin, nearly constant velocity of about+17 cm/s for the first second, then changes tonegative velocity. Acceleration changes from zero (first second), to negative, to positive (at about 2seconds). Object "disappears or data is lost from 3 -4 seconds.* (sm)富

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Answered: 1. For each of the following graphs,…

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2. Position vs. time: a.Type of graph: Scatter b.X: elapsed time, Δt. Column D. c.Y: position (m). Column F. d.Trendline: Polynomial, 2nd degree. Show the equation and set the y-intercept on your chart to zero. e.Your Third value for acceleration lies here.
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1. A motorized toy car moves at a constant velocity of 4 m/s. You start recording its motion at zero time as it passes a point 2 m from the zero-position point. a. Sketch a position vs. time graph for the toy car. Be sure you include appropriate labels and units for each axis. b. How can you find the velocity of the car from the position vs. time graph? c. Write an equation for the graph using the proper variables and units.
D, E, and F
1, 2. 3. 5. 9, Table 2. 2: Passenger Jeepney's Motion Distance d Time t (m) (4) 4. 150 7. 8.
How would you expect a velocity vs. time graph to look for a cart moving with a constant velocity? Make a rough sketch of the graph and explain your reasoning. Write down an equation for the graph. Explain what the symbols in each of the equations mean. What quantities in these equations can you determine from your graph? Write down the relationship between the position and the velocity of the cart. Use that relationship to construct an position versus time graph just below each of your velocity versus time graphs from question 1, with the same scale for each time axis. Write down an equation for the new graph. Explain what the symbols in each of the equations mean. What quantities in these equations can you determine from your graph? Consider the questions printed in italics, below, to make a rough sketch of how you expect the velocity vs. time graph to look for a cart under the conditions given in the problem. Explain your reasoning. Since a simple push of the lego car…
5. A Learning Task 2B: Analyzing Motion Graph Practice on how to create motion graphs by choosing the appropriate graph for a given situation. Draw your answer on a piece of paper, refer to the sample graphs provided below: bno ran noilor or psylon ni bine entw. c) distance Figure 4. Sample Graphs 1. Ana's car is travelling at 45 kilometers for 0.50 hours when her vehicle stopped at a stop light. Ayod tocolpipot on 2. A vehicle is at rest when it started to move at 15 kilometers for 5 minutes before increasing its speed to 35 kilometers for another 15 meters. 3. Jose rode a bike to his school at the constant speed.
Include a picture or description of your coordinate system (origin, positive direction).
2. The position of a drone as a function of time is given by *(t) = ( 8 i + 1.5 k) + (-3 î + 2 j) t – 0.5 t2 j The units are missing in the constant coefficients above, i.e., "0.5" should be "0.5 m/s2". Include the correct units on all the constant coefficients in your answers below. a. What is the x-position of the drone as a function of time? b. What is the y-position of the drone as a function of time? c. How far away is the drone from its starting position at t = 3s? d. What is the acceleration vector? е. What is the velocity vector as a function of time? (One way to do this is to take the time derivative of the position vector.) f. Make a sketch of the x, y, and z positions of the drone as function of time. You just need the general shape. time time time
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6. A train is moving with a constant speed. The train moves 60 meters for every 1.5 seconds that elapses. a. Assume that we get 40 by dividing 60 by 1.5. What is the name that is commonly given to a quantity represented by this number 40? b. To denote the quantity completely, what additional information must be given besides the number 40? c. How would you interpret the number 40 in this instance? Your answer should mention distance and time. d. Use your interpretation (not algebra) to find the distance the train moves in 2.5 seconds.
only J, K, and L

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