1. For an experiment, a biology student makes 1 liter of a solution containing the following substances, which are shown in the table below. Using the given information, fill in the missing parts of the table for each substance by (a) providing the formula weight and (b) calculating either the mass the student needs to weigh out or the number of moles that the student has, based on the amount weighed out. For each calculation, show your work. Be sure to include the formula mass of water for CaC12 • 2H2O and NaH2PO4 H2O. . Substance Mass (g) Answor NaCl KCI C6H12O6 NaHCO3 CaCl2 • 2H2O MgSO4 NaH2PO4 H2O Formula Weight (g/mol) Number of Moles 0.14 0.005 0.0262 0.0008 1.01 0.15 0.14

1. For an experiment, a biology student makes 1 liter of a solution containing the following substances, which are shown in the table below. Using the given information, fill in the missing parts of the table for each substance by (a) providing the formula weight and (b) calculating either the mass the student needs to weigh out or the number of moles that the student has, based on the amount weighed out. For each calculation, show your work. Be sure to include the formula mass of water for CaC12 • 2H2O and NaH2PO4 H2O. . Substance Mass (g) Answor NaCl KCI C6H12O6 NaHCO3 CaCl2 • 2H2O MgSO4 NaH2PO4 H2O Formula Weight (g/mol) Number of Moles 0.14 0.005 0.0262 0.0008 1.01 0.15 0.14

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter4: Types Of Chemical Reactions And Solution Stoichiometry

Section: Chapter Questions

Problem 20Q: A student wants to prepare 1.00 L of a 1.00-M solution of NaOH (molar mass = 40.00 g/mol). If solid...

See similar textbooks

Similar questions

A solution is 0.1% by mass calcium chloride. Therefore, 100. g of the solution contains g of calcium chloride.
The following claim is made in your text: 1 mole of marbles is enough to cover the entire earth to a depth of 50 miles. Provide mathematical support for this claim. Is it reasonably accurate?
The units of parts per million (ppm) and parts per billion (ppb) are commonly used by environmental chemists. In general, 1 ppm means 1 part of solute for every 106 parts of solution. Mathematically, by mass: ppm=gsolutegsolution=mgsolutekgsolution In the case of very dilute aqueous solutions, a concentration of 1.0 ppm is equal to 1.0 g of solute per 1.0 mL, which equals 1.0 g solution. Parts per billion is defined in a similar fashion. Calculate the molarity of each of the following aqueous solutions. a. 5.0 ppb Hg in H2O b. 1.0 ppb CHCl3 in H2O c. 10.0 ppm As in H2O d. 0.10 ppm DDT (C14H9Cl5) in H2O
The empirical formula of a gaseous fluorocarbon is CF2 . At a certain temperature and pressure, a 1-L volume holds 8.93 g of this fluorocarbon, whereas under the same conditions, the 1-L volume holds only 1.70 g gaseous fluorine (F2) . Determine the molecular formula of this compound.
A 0.755-g sample of hydrated copper(II) sulfate CuSo4xH2O was heated carefully until it had changed completely to anhydrous copper(II) sulfate (CuSO4 ) with a mass of 0.4183 g. Determine the value of x. [This number is called the number of waters of hydration of copper(II) sulfate. It specifies the number of water molecules per formula unit ofCuSO4 in the hydrated crystal.]
A chemist prepared a compound that she thought had the formula FeI3. When the compound was analyzed, it contained 18.0% Fe and 82.0% I. Calculate the mass percentage composition expected for FeI3 and compare the result with that found in the analysis. Is this the correct formula of the compound?
An average adult breathes about 8.50103 L of air per day. The concentration of lead in highly polluted urban air is 7.0106 g of lead per one m3 of air. Assume that 75% of the lead is present as particles less than 1.0106 m in diameter, and that 50% of the particles below that size are retained in the lungs. Calculate the mass of lead absorbed in this manner in 1 year by an average adult living in this environment.
When 9.59 g of a certain vanadium oxide is heated in the presence of hydrogen, and a new oxide of vanadium are formed. This new vanadium oxide has a mass of 8.76 g. When the second vanadium oxide undergoes additional heating in the presence Of hydrogen, 5.38 g of vanadium metal forms, a. Determine the empirical formulas for the two vanadium oxides. b. Write balanced equations for the Steps of the reaction. c. Determine the mass of hydrogen needed to complete the steps of this reaction.
How many molecules of C2H4Cl2 can be prepared from 15C2H4 molecules and 8Cl2 molecules?
It sodium peroxide is added to water, elemental oxygen gas is generated: :math>Na2O2(s)+H2O(l)NaOH(aq)+O2(g) ppose 3.25 g of sodium peroxide is added to a large excess of water. What mass of oxygen gas will be produced?
The meat from one hazelnut has a mass of 0.985 g. (a) What is the mass of a millionth of a mole (106) of hazelnut meats? (A millionth of a mole is also called a micromole.) (b) How many moles are in a pound of hazelnut meats?
A dark brown binary compound contains oxygen and ametal. It is 13.38% oxygen by mass. Heating it moderatelydrives off some of the oxygen and gives a red binary compoundthat is 9.334% oxygen by mass. Strong heatingdrives off more oxygen and gives still another binary compound,which is only 7.168% oxygen by mass. (a) Compute the mass of oxygen that is combined with1.000 g of the metal in each of these three oxides. (b) Assume that the empirical formula of the first compoundis MO2 (where M representsthe metal). Givethe empirical formulas of the second and thirdcompounds. (c) Name the metal.