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1. Fig. 1 contains the 70 eV electron impact mass spectrum of a compound whose combustion analysis was found to be: Carbon, 71.98 %; Hydrogen, 6.71 %. Deduce with empirical formula, the molecular formula and calculate the degree of unsaturation. How would you confirm that the Molecular Ion had indeed a value of 150? 100 80 60 40 20 % of base peak 40 91 80 119 M+¹= 150 120 160 m/e

1. Fig. 1 contains the 70 eV electron impact mass spectrum of a compound whose combustion analysis was found to be: Carbon, 71.98 %; Hydrogen, 6.71 %. Deduce with empirical formula, the molecular formula and calculate the degree of unsaturation. How would you confirm that the Molecular Ion had indeed a value of 150? 100 80 60 40 20 % of base peak 40 91 80 119 M+¹= 150 120 160 m/e

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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1. Fig. 1 contains the 70 eV electron impact mass spectrum of a compound whose combustion analysis was found to be: Carbon, 71.98%; Hydrogen, 6.71 %. Deduce with empirical formula, the molecular formula and calculate the degree of unsaturation. How would you confirm that the Molecular Ion had indeed a value of 150? 100 80 60 40 20 % of base peak 40 91 80 Fig. 1 119 120 M+= 150 160 m/e
Transcribed Image Text:1. Fig. 1 contains the 70 eV electron impact mass spectrum of a compound whose combustion analysis was found to be: Carbon, 71.98%; Hydrogen, 6.71 %. Deduce with empirical formula, the molecular formula and calculate the degree of unsaturation. How would you confirm that the Molecular Ion had indeed a value of 150? 100 80 60 40 20 % of base peak 40 91 80 Fig. 1 119 120 M+= 150 160 m/e
Expert Solution
Step 1

Given

A compound whose combustion analysis was found

C = 71.98 %

H = 6.71 %

And a mass spectrum of given molecule.

steps

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