1. Determine the upper- and lower-tail critical values of t in each of the following two-tests assuming that the variances of the two populations are equal.a) a = .10, n1 = 16, n2 = 21b) a = .05, n1 = 20, n2 = 25c) a = .02, n1 = 10, n2 = 12%3Dd) a = .05, n1 = 8,n2 = 9%De) a = .01, n1 = 12, n2 =12%3D

as per our company guidelines we are supposed to answer only first 3 sub-parts. Kindly repost other…

Answered: 1. Determine the upper- and lower-tail…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Suppose we wish to compare the variation in diameters of parts produced by company A with the variation in diameters of parts produced by company B. The sample variance of company A, based on n = 19 diameters, was, s1 2 = 0.0012, while the sample variance of the 20 diameter measurements from the company B has sample variance, s2 2 = 0.0017. Do the data provide sufficient information to indicate a larger variance in diameters for company B?. Test with X = 0.1.
The standard z-value of an arbitrary 16-unit sample from the normal-class population with a mean of 60 and a variance of 100 is 2.0.
Two accounting professors decided to test if the variance of their grades is different or no. To accomplish this, they each graded the same 10 exams with the following results: Standard Grade þeviation 22.4 12.0 Мean Professor 1 Professor 2 79.3 82.1 F What is the P-value of the test? Select one: Oa. between 0.01 and 0.025 Ob. between 0.025 and 0.05 c. between 0.05 and 0.10 Od. bigger than 0.10
An electronic company's records show that the mean number of circuit.boards rejected per batch is 5.7 with a variance of 1.4. Due to a change in the molding process, factory management has hired you to perform a hypothesis test to check if the variance, o, has increased. To do so, you test a random sample of 10 batches produced using the new process; the number of circuit boards rejected per batch has a sample variance of 2.5. Under the assumption that the number of circuit boards rejected per batch using the new process follows a normal distribution, you will perform a chi-square test. Find x, the value of the test statistic for your chi-square test. Round your answer to three or more decimal places. * = 0
The amount of chlorine in 100 cm3 water taken from a water tank was measured, the average was 2.15 mg was found. The expert claims that the amount of chlorine in the water is greater than that measured. For this reason, 100 households were randomly selected, with an average chlorine content of 2.55mg and a variance of 0.49 mg. According to this data, find the account value z. 13 - O A) 8,15 O B) 5,71 O C) -5,71 O D) -8, 15 O E) 0.54
A new study has found that, on average, 6- to 12-year-old children are spending less time on household chores today compared to 1981 levels. Suppose two samples representative of the study's results report the following summary statistics for the two periods. 1981 Levels 2008 Levels 24 minutes 19 minutes 51 = 3.5 minutes 52 - 4.3 minutes ni = 30 n2 - 30 Which of the following is the correct value of the test statistic assuming that the unknown population variances are equal? Multiple Cholce Z = -4.94 tss = 4.94 Z = 4.94 t59 = -4.94
There are two samples. Sample 1 has n=10 and a sample variance of 4. Sample 2 has n=8 and a sample variance of 9. Calculate the standard error of the difference between the two sample means (to 2 decimal points). Assume that the variances in the two populations that produced the samples are equal.
The number of dollars a round trip plane ticket costs from North America to Europe is normally distributed with a mean of $1,780 and a standard deviation of $335. What is the probability a randomly selected ticket costs between $775 and $2,785? Enter your answer in decimal form. For example. 75% should be entered as 0.75
Assume that the examination marks of students follow normal distri- butivn with unknown mean (4) but known variance (a?) = 0.25. Test the hypothesis Ho : u =8 against H: #8 with the level of significance a = 0.01, the sample mean being equal to 7.8 and the sample size being 50.
5. We don't want predictor variables that are too highly correlated with each other or they are redundant (say ≥±.70) or multicollinear (2±.90), which means the variables are measuring pretty much the same thing so why have them all in the equation. What was the finding for redundancy between SPI Scientist and SPI Practitioner? a. No issue with redundancy since the shared variance between the two variables was only 4% (r2 = .04). b. There was an issue with redundancy between the two variables shared 62% of the variance in the relationship.
A researcher decides to measure anxiety in group of bullies and a group of bystanders using a 23-item, 3 point anxiety scale. Assume scores on the anxiety scales are normally distributed and the variance among the group of bullies and bystanders are the same. A group of 30 bullies scores an average of 21.5 with a sample standard deviation of 10 on the anxiety scale. A group of 27 bystanders scored an average of 25.8 with a sample standard deviation of 8 on the anxiety scale. You do not have any presupposed assumptions whether bullies or bystanders will be more anxious so you formulate the null and alternative hypothesis based on that.

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS