1. Count the atoms for each element in the for (C:N.).N NaHCO,

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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4. Count the atoms for each element in the formulas.
(C:N.):N
NaHCO,
2H2SO4
Bas(PO.)2
ЗА(ОН),
5KNOS
2CH.COCH,
Ca(NO:):
2CSHS
Transcribed Image Text:4. Count the atoms for each element in the formulas. (C:N.):N NaHCO, 2H2SO4 Bas(PO.)2 ЗА(ОН), 5KNOS 2CH.COCH, Ca(NO:): 2CSHS
Expert Solution
Explanation:

Given molecule :

first molecule :(C2N4)2N

1 mole mole of any chemical substance contains Avogadro's number of atoms /molecules/ions ....etc

here the molecule has 4 moles of C atoms and (8N+1N)=9 moles of N atoms present 

No.of Carbon (C) atoms are:

4 x 6.023 x 1023 atoms =2.4092 x 1024 atoms of Carbon

No.of Nitrogen atoms (N):

9 x 6.023 x 1023 atoms =5.4207 x 1024 atoms of Nitrogen

 

For second molecule: NaHCO3 

1 mole of NaHCO3 contains 1 mole of Na atom , 1 mole of H atom ,1 moles of C atom and 3 moles of  Oxygen atoms are present 

No.of Sodium (Na) atoms:

1 x 6.023 x 1023 atoms =6.023 x 1023 Na atoms

No.of Carbon atoms:

1 x 6.023 x 1023 atoms =6.023 x 1023 C atoms

No.of Hydrogen atoms:

1 x 6.023 x 1023 atoms =6.023 x 1023 H atoms

No.of Oxygen atoms :

3 x 6.023 x 1023 atoms =1.8069 x 1024 O atoms 

 

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