1. Consider our Sun - it is in orbit around the center of our Milky Way Galaxy. The velocity of the Sun in its orbit is about 250 km/s. The distance to the center of the galaxy is about 9.1 kpc (kiloparsecs). We can use Kepler's third law to calculate the mass of the galaxy interior to the Sun's orbit. We assume that the orbit is circular so that the semimajor axis is just the radius of the circular orbit = 9.1 kpc. First we need to calculate the number of AU's in 9.1 kpc. (Note that 1 kpc = 1000 pc = 3260 Įt yrs and 1 pc = 206,265 AU. ) 1000 pc | 206,265.4U a =r = 9.1kpc = (9.1žpc) AU Sun 1 nc

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1. Consider our Sun - it is in orbit around the center of our Milky Way Galaxy.
The velocity of the Sun in its orbit is about 250 km/s. The distance to the center
of the galaxy is about 9.1 kpc (kiloparsecs). We can use Kepler's third law to
calculate the mass of the galaxy interior to the Sun's orbit. We assume that the
orbit is circular so that the semimajor axis is just the radius of the circular orbit =
9.1 kpc. First we need to calculate the number of AU's in 9.1 kpc. (Note that 1
Крс - 1000 рс - 3260 1t yrs and 1 pc - 206,265 AU.)
%3D
a =r =9.1kpc = (9.1kpc) 1000 pc 206,265AU]
1kpc
AU
Sun
1pc
Transcribed Image Text:1. Consider our Sun - it is in orbit around the center of our Milky Way Galaxy. The velocity of the Sun in its orbit is about 250 km/s. The distance to the center of the galaxy is about 9.1 kpc (kiloparsecs). We can use Kepler's third law to calculate the mass of the galaxy interior to the Sun's orbit. We assume that the orbit is circular so that the semimajor axis is just the radius of the circular orbit = 9.1 kpc. First we need to calculate the number of AU's in 9.1 kpc. (Note that 1 Крс - 1000 рс - 3260 1t yrs and 1 pc - 206,265 AU.) %3D a =r =9.1kpc = (9.1kpc) 1000 pc 206,265AU] 1kpc AU Sun 1pc
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