1. Calculate the final temperature for each of the following mixtures. Assume no heat loss to the environment. Show your method for part b. a. 50.0 mL of water at 25.0°C is mixed with 50.0 mL of water at 85.0°C. b. 75.0 g of water at 25.0°C is mixed with 25.0 g of water at 85.0°C.
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
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EXPERIMENT 10
DETERMINATION OF HEAT OF REACTION
1. Calculate the final temperature for each of the following mixtures. Assume no heat loss
to the environment. Show your method for part b.
a. 50.0 mL of water at 25.0°C is mixed with 50.0 mL of water at 85.0°C.
Name
b. 75.0 g of water at 25.0°C is mixed with 25.0 g of water at 85.0°C.
2. a. In Part B of this experiment, 0.10g of Mg is added to 50. mL of 1.0M HC1. Which is
the limiting reactant? Show calculations.
b. In Part C, 0.25 g of MgO is added to 50.mL of 1.0M HC1. Which is the limiting
reactant?
3. When 50.0mL of 1.00M H₂SO4 at 26.1°C was added to 50.0mL of 1.00M NaOH also
at 26.1°C, the temperature rose to 32.6°C. Assume the resulting solution had a total
volume of 100.0 mL with the same density and specific heat as water. Calculate AH for
the reaction described by this equation.
H₂SO4(aq) + 2 NaOH(aq) → Na2SO4(aq) + 2 H₂O(1)
Steps: Which reactant limits? How many moles of it are present?
How much energy required to heat
100.0g solution from 26.1°C to 32.6°C?
How much energy is released by the reaction
per one mole of the limiting reactant?
How many moles of that reactant
are in the given equation?
What is AH in kJ (not kJ/mol)?
Show calculations here:"
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