### Physics Problem on Conservation of Energy**Problem Statement:**As shown in the figure:- \( m_1 = 1.4 \, \text{kg} \)- \( m_2 = 5.4 \, \text{kg} \)- \( m_3 = 8.6 \, \text{kg} \) Masses 1 and 3 are on the ends of a weightless rope which does not slip as it goes over the disk. Mass 2 is a solid disk of radius \( R = 36 \, \text{cm} \). The moment of inertia of the disk is \( I_2 = \frac{1}{2} m_2 R^2 \).- Mass 1 is initially resting on the floor.- Mass 3 is suspended at a height \( h = 1.4 \, \text{m} \).When released, mass 3 falls toward the floor. Using the conservation of energy, determine:1. The velocity of the system just before \( m_3 \) hits the floor.2. The angular velocity of the disk.3. The kinetic energy of each mass at this time.**Explanation and Calculations:**1. **Determine the Velocity of the System:** To find the velocity of the masses and disk, apply the conservation of mechanical energy. Initially, only mass 3 has gravitational potential energy (since it is at height \( h \)) and there is no kinetic energy. Just before mass 3 hits the floor, all of this potential energy would be converted into kinetic energy of masses 1, 2 (disk), and 3. 2. **Calculate the Angular Velocity of the Disk:** Use the relationship between linear velocity \( v \) and angular velocity \( \omega \) of the disk: \( v = \omega R \).3. **Find the Kinetic Energy of Each Mass:** Calculate the kinetic energy of each mass using the formula: - For translational motion: \( KE_{\text{translational}} = \frac{1}{2} m v^2 \) - For rotational motion of the disk: \( KE_{\text{rotational}} = \frac{1}{2} I \omega^2 \)These steps will allow solving for the corresponding velocities and kinetic energies based on the principles of conservation of energy. This diagram depicts a classical physics problem involving three masses (\(m_1\), \(m_2\), and \(m_3\)), a pulley of radius \(R\), and a falling distance \(l\). Below is an explanation and transcription of the diagram suitable for an educational website:### DescriptionIn the diagram, a system comprising three masses (\(m_1\), \(m_2\), and \(m_3\)) is depicted. The masses are connected by a rope over a pulley.### Detailed Explanation1. **Mass \(m_1\)**: This mass (\(m_1\)) lies on a horizontal surface. 2. **Mass \(m_2\)**: This is the mass attached to the rope which passes over a pulley. The pulley has a radius \(R\).3. **Mass \(m_3\)**: This mass (\(m_3\)) is suspended in the air and can move vertically.The system is typically used to study the principles of mechanics, including forces and motion when different masses are connected over a pulley.1. **Pulley and Radius \(R\)**: - The pulley is depicted as a circle with a connecting radius \(R\). This radius is crucial for calculating the torque and moment of inertia involving the pulley system.2. **Vertical Movement and Distance \(l\)**: - \(l\) is the vertical distance traveled by the mass \(m_3\). This distance is measured from a reference point.### Transcription of Labels- \(R\): Radius of the pulley.- \(m_1\): Mass 1 placed on the ground level.- \(m_2\): Mass 2 which is on the pulley.- \(m_3\): Mass 3 which hangs vertically.- \(l\): Vertical distance.This setup illustrates the interplay of gravitational forces, tension in the rope, and rotational motion in a pulley system. Calculations often involve Newton's Second Law, equations of motion, and energy conservation principles to analyze the movement and forces within this system.

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Answered: = 1. As shown in the figure m₁ 1.4kg,…

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