1. An electron initially moves in a horizontal directionand has a kinetic energy of 2 × 103 eV (electron-volts) when it enters to the electric field E as shownin the figure. It passes through a uniform electric fieldbetween two oppositely charged vertical plates to afield-free region with a velocity 2.8 x 10'm/s. Theplates are separated from each other by a distance of0.04 meter. Gravity is negligible.0.04mElectronCalculate electric field and find its direction:Lme = 9.11 x 10-31kg; qe = -1.6 × 10-1ºC;1eV = 1.6 x 10¬19]Hint:1Kinetic energy =qEmv²; Potential energy =dUse conservation of energy.(A)5800 V/m; directed from R to L(B) 5800 V/m; directed from L to R(C) 6750 V/m; directed from R to L(D)6750 V/m; directed L from to R(E) None of them

Answered: 1. An electron initially moves in a…

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