1. Acid-base equilibriuma.. Draw the major resonance contributors of the product structures for each acid-base reaction below.b. Use the pKa data from lecture to estimate the pKa of each acid / conjugate acid.Calculate Keq for each reaction and draw the corresponding equilibrium arrow.c.iHacid1 pka =ΝΗacidpka =O=S=HO-S-OHOacidipka =NLibaseONabaseNH人base(equilibrium arrow)Kea11(equilibrium arrow)BKegKeg=!(equilibrium arrow)1T11111111I1NLIeconjugate baseconjugate baseconjugate base1Hconjugate acid¦pka =conjugate acidpka =conjugate acidpka =1

Acidity is defined as the ability of a molecule to release protons.If a compound easily donates…

1. Acid-base equilibrium a. Draw the major resonance contributors of the product structures for each acid-base reaction below. b. Use the pKa data from lecture to estimate the pKa of each acid / conjugate acid. Calculate Keq for each reaction and draw the corresponding equilibrium arrow. c. i H acid :pka = NH acid pka = 0=60=0 HO-S-OH acid pka = NLi base ONa base NH base Kea (equilibrium arrow) Keg (equilibrium arrow) Keq (equilibrium arrow) NLI conjugate base conjugate base conjugate base conjugate acid pka = conjugate acid pka = conjugate acid 1 pka =

1. Acid-base equilibrium a. Draw the major resonance contributors of the product structures for each acid-base reaction below. b. Use the pKa data from lecture to estimate the pKa of each acid / conjugate acid. Calculate Keq for each reaction and draw the corresponding equilibrium arrow. c. i H acid :pka = NH acid pka = 0=60=0 HO-S-OH acid pka = NLi base ONa base NH base Kea (equilibrium arrow) Keg (equilibrium arrow) Keq (equilibrium arrow) NLI conjugate base conjugate base conjugate base conjugate acid pka = conjugate acid pka = conjugate acid 1 pka =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

[References] Answer questions a-c about the Bronsted acid-base reaction below using the identifying letters A-D below each structure. The pKa's for the acids of interest are: acetic acid (pK, 4.8), and hydrogen bromide (pK,=-9). CH3 Br CH3 H-Br OH B acetic acid bromide acetate hydrogen bromide a) The stronger base is b) Its conjugate acid is c) The species that predominate at equilibrium are (two letters, e.g. ac) Submit Answer Try Another Version 1 item attempt remaining Visited Previous Nex Email Instructor Sav Cengage Learning | Cengage Technical Support
4. For each of the following molecules, circle the most acidic (unstable) hydrogen atom and estimate its pka value. You may need to draw in the most acidic hydrogen if it is implied. CH3 50 pka : HO H₂O H₂N NH₂ OH OH pka : pka : pka : pka:
Draw the product of the reaction shown below at physiological pH (pH = 7.4). Ignore inorganic byproducts. esc N Z I H O mi Br 2 NH3 2 H₂O Drawing F2 #3 20 F3 OH 000 000 F4 4 de Lo % F5 5 At 2 Draw MacE
10 eBook Print r References Select the best base to quantitatively remove a proton from acetylene. Multiple Choice O O NaNH2 NH3 NaOH NaOCH2CH3
acid conjugate base j Acetic pKa || rite whether the pr (You do not need to s Acid Hy pK
Answer questions a-c about the Bronsted acid-base reaction below using the identifying letters A-D below each structure. The pka's for the acids of interest are: ethylammonium ion (pK₂ = 10.8), and hydrogen chloride (pK₂ = -7). NH₂ A ethylamine Submit Answer + H CI B hydrogen chloride CH3 NH3 с ethylammonium + CI D chloride a) The stronger acid is b) Its conjugate base is c) The species that predominate at equilibrium are (two letters, e.g. ac) Retry Entire Group 2 more group attempts remaining
Match the following structures to the appropriate pKa value. А. F,CHCOOH B. CI3CCOOH C. CH3COOH D. CICH,COOH Е. BrCH,COOH 4.8 2.86 2.8 1.24 0.6
1. For each set, rank the acids by putting a "1" under the weakest acid (highest--most positive-- expected pka), then a "2" under the next most weakest, then a "3" under the next most weakest then a "4" under the strongest acid (highest--most positive-- expected pKa) briefly explain why. H₂ Te a. H₂Se b. HC1 C. H₂S H₂S MOM OH H₂O SIH4 PH 3 OH -Ō OH OH
help
K Draw the product of the reaction shown below at physiological pH (pH = 7.4). Ignore inorganic byproducts. esc F1 1. NH4Cl, NaCN O 2. HCI, H₂O, heat Drawing F2 # F3 Q $ 000 F4 % F5 F Atom anc Draw or MacBo