1. A wet gas from a field in Iran is processed through two stages of separation; first stage separator operates at 220 psia and 71°F, while the stock tank operates at atmospheric pressure and 69°F. The separator gas condensate ratio is 41,000 scf/STB and the stock tank gas condensate ratio is 450 scf/STB. The molecular weights of the separator gas and stock tank gas are 25.0 and 35.0 lb/lb-mol, respectively. The stock tank condensate gravity is 0.85 and its molecular weight is 125 lb/lb-mol. Let us calculate the specific gravity of the reservoir gas in a step-wise manner, by considering quantities for one STB of condensate. Note that 1.0 bbl is 5.614 ft. Separator gas MWsg = 25 lb/lb-mol 41,000 scf/STB Reservoir gas 1st stage separator 220 psia and 71°F Stock tank gas MWsg = 35 lb/lb-mol 450 scf/STB 2nd stage separator (Stock tank) 14.7 psia and 69°F MW=125 lb/lb-mol SGstc = 0.85 Stock tank condensate a. to one STB. Calculate the mole number [lb-mole] of the stock tank condensate that corresponds b. Calculate the mole number [lb-mole] of the stock tank gas that is produced with one STB of condensate. Use the ideal gas EOS. C. Similarly, calculate the mole number [lb-mole] of the separator gas that is produced with one STB of condensate. Use the ideal gas EOS. d. C. Calculate the average molecular weight of the reservoir gas based on Parts a, b, and e. Calculate the specific gravity of the reservoir gas. The molecular weight of air is 28.96 [lb/lb-mol]. f. Calculate the gas formation volume factor at reservoir conditions of 2000 psia and reservoir use the 100°F for the gas. https://checalc.com/solved/naturalgasZ.html You may website:
1. A wet gas from a field in Iran is processed through two stages of separation; first stage separator operates at 220 psia and 71°F, while the stock tank operates at atmospheric pressure and 69°F. The separator gas condensate ratio is 41,000 scf/STB and the stock tank gas condensate ratio is 450 scf/STB. The molecular weights of the separator gas and stock tank gas are 25.0 and 35.0 lb/lb-mol, respectively. The stock tank condensate gravity is 0.85 and its molecular weight is 125 lb/lb-mol. Let us calculate the specific gravity of the reservoir gas in a step-wise manner, by considering quantities for one STB of condensate. Note that 1.0 bbl is 5.614 ft. Separator gas MWsg = 25 lb/lb-mol 41,000 scf/STB Reservoir gas 1st stage separator 220 psia and 71°F Stock tank gas MWsg = 35 lb/lb-mol 450 scf/STB 2nd stage separator (Stock tank) 14.7 psia and 69°F MW=125 lb/lb-mol SGstc = 0.85 Stock tank condensate a. to one STB. Calculate the mole number [lb-mole] of the stock tank condensate that corresponds b. Calculate the mole number [lb-mole] of the stock tank gas that is produced with one STB of condensate. Use the ideal gas EOS. C. Similarly, calculate the mole number [lb-mole] of the separator gas that is produced with one STB of condensate. Use the ideal gas EOS. d. C. Calculate the average molecular weight of the reservoir gas based on Parts a, b, and e. Calculate the specific gravity of the reservoir gas. The molecular weight of air is 28.96 [lb/lb-mol]. f. Calculate the gas formation volume factor at reservoir conditions of 2000 psia and reservoir use the 100°F for the gas. https://checalc.com/solved/naturalgasZ.html You may website:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![1.
A wet gas from a field in Iran is processed through two stages of separation; first
stage separator operates at 220 psia and 71°F, while the stock tank operates at atmospheric
pressure and 69°F. The separator gas condensate ratio is 41,000 scf/STB and the stock tank gas
condensate ratio is 450 scf/STB. The molecular weights of the separator gas and stock tank gas
are 25.0 and 35.0 lb/lb-mol, respectively. The stock tank condensate gravity is 0.85 and its
molecular weight is 125 lb/lb-mol. Let us calculate the specific gravity of the reservoir gas in a
step-wise manner, by considering quantities for one STB of condensate. Note that 1.0 bbl is
5.614 ft.
Separator gas
MWsg = 25 lb/lb-mol
41,000 scf/STB
Reservoir gas
1st stage separator
220 psia and 71°F
Stock tank gas
MWsg = 35 lb/lb-mol
450 scf/STB
2nd stage separator
(Stock tank)
14.7 psia and 69°F
MW=125 lb/lb-mol
SGstc = 0.85
Stock tank condensate
a.
to one STB.
Calculate the mole number [lb-mole] of the stock tank condensate that corresponds
b.
Calculate the mole number [lb-mole] of the stock tank gas that is produced with one
STB of condensate. Use the ideal gas EOS.
C.
Similarly, calculate the mole number [lb-mole] of the separator gas that is produced
with one STB of condensate. Use the ideal gas EOS.
d.
C.
Calculate the average molecular weight of the reservoir gas based on Parts a, b, and
e.
Calculate the specific gravity of the reservoir gas. The molecular weight of air is
28.96 [lb/lb-mol].
f.
Calculate the gas formation volume factor at reservoir conditions of 2000 psia and
reservoir
use the
100°F
for
the
gas.
https://checalc.com/solved/naturalgasZ.html
You
may
website:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F56cdd5c4-e052-450c-a2b2-1366c7cbfa01%2Fca9daa95-2b20-4861-8d1e-b75922700871%2Fy3b77v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1.
A wet gas from a field in Iran is processed through two stages of separation; first
stage separator operates at 220 psia and 71°F, while the stock tank operates at atmospheric
pressure and 69°F. The separator gas condensate ratio is 41,000 scf/STB and the stock tank gas
condensate ratio is 450 scf/STB. The molecular weights of the separator gas and stock tank gas
are 25.0 and 35.0 lb/lb-mol, respectively. The stock tank condensate gravity is 0.85 and its
molecular weight is 125 lb/lb-mol. Let us calculate the specific gravity of the reservoir gas in a
step-wise manner, by considering quantities for one STB of condensate. Note that 1.0 bbl is
5.614 ft.
Separator gas
MWsg = 25 lb/lb-mol
41,000 scf/STB
Reservoir gas
1st stage separator
220 psia and 71°F
Stock tank gas
MWsg = 35 lb/lb-mol
450 scf/STB
2nd stage separator
(Stock tank)
14.7 psia and 69°F
MW=125 lb/lb-mol
SGstc = 0.85
Stock tank condensate
a.
to one STB.
Calculate the mole number [lb-mole] of the stock tank condensate that corresponds
b.
Calculate the mole number [lb-mole] of the stock tank gas that is produced with one
STB of condensate. Use the ideal gas EOS.
C.
Similarly, calculate the mole number [lb-mole] of the separator gas that is produced
with one STB of condensate. Use the ideal gas EOS.
d.
C.
Calculate the average molecular weight of the reservoir gas based on Parts a, b, and
e.
Calculate the specific gravity of the reservoir gas. The molecular weight of air is
28.96 [lb/lb-mol].
f.
Calculate the gas formation volume factor at reservoir conditions of 2000 psia and
reservoir
use the
100°F
for
the
gas.
https://checalc.com/solved/naturalgasZ.html
You
may
website:
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