GENERAL-PHYSICS-4TH-MODULE-2 - WordSign inViewO Search& ShareFileHomeInsertDesignLayoutReferencesMailingsReviewHelpL X.. , 1. . . , . . 2 ... .. , 3. , . . , .... . . 6What I Have LearnedInstruction:Solve the following problems neatly and completely in a one (1) whole sheet of intermediate or yellowраper.1. A particle with a charge of –1.24 x 108 C is moving with instantaneous velocity v =(1.49 ×104m_)i+(-3.85×104m_)j. What is the force exerted on this particle by a magneticfield (a) B` = (1.40 T)î+(-2.30 T)k and (b) B¯ = (-1.25 T)î+(2.00 T)j+(-3.50 T)K?%3DPage 8 of 174420 wordsE English (Philippines)+ 160%10:24 PMwA O d)08/05/2021

Given that- Q=-1.24×10-8 CV=(1.49i-3.85j)×104 m/sa)For B=(1.40 T)i+(-2.30 T)kforce acting on the…

1. A particle with a charge of –1.24 x 108 C is moving with instantaneous velocity v = (1.49 ×104 m_)î+(-3.85×104m_)j. What is the force exerted on this particle by a magnetic field (a) B¯ = (1.40 T)î+(-2.30 T)k and (b) B¯ = (-1.25 T)î+(2.00 T)j+(-3.50 T)k? %3D

1. A particle with a charge of –1.24 x 108 C is moving with instantaneous velocity v = (1.49 ×104 m_)î+(-3.85×104m_)j. What is the force exerted on this particle by a magnetic field (a) B¯ = (1.40 T)î+(-2.30 T)k and (b) B¯ = (-1.25 T)î+(2.00 T)j+(-3.50 T)k? %3D

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A proton (charge = 1.6 × 10−19 C, mass = 1.67 x 10-27kg) is moving into constant magnetic field B =…

Q: A deuteron (the nucleus of an isotope of hydrogen) has a mass of 3.34×10−27 kg and a charge of…

Q: A long straight horizontal wire carries a current I= 1.80 A to the left. A positive 1.00 C charge…

Q: An electron in a TV CRT moves with a speed of 6.00 X 107 m/s,in a direction perpendicular to the…

A: velocity, v = 6 X 107 m/s magnetic field, B = 5 X 10-5 T

Q: At what speed would a proton need to circle the Earth at a height of 1000 km above the equator if…

Q: A proton moves through a region of space where there is a magnetic field B = (0.491 + 0.40]) T and…

Q: Triply charged uranium-235 and uranium-238 ions are being separated in a mass spectrometer. (The…

Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.38 T. If the…

A: (a) speed of the electron

Q: A particle with a charge of −1.24×10−8C is moving with instantaneous velocity v = (4.19×104m/s)i +…

Q: 2. A proton traveling at 1*10^7 m/s in a horizontal plane passes through an opening into a mass…

Q: hat is the radius of a proton's trajectory when it moves at 2.4x106 m/s perpendicular to a magnetic…

A: Given: The speed of the proton is 2.4x106 m/s perpendicular to the magnetic field. The strength of…

Q: You want to determine the mass of an unknown particle, X. You ionize the particle, by removing an…

Q: A 1500 kg car moves west along the equator. At this location Earth's magnetic field is 3.5 × 10^−5 T…

A: Given Data, Mass of the car (m)=1500 kg The Earth's Magnetic Field (B)=3.5 × 10−5 T Charge (q)=-2.5…

Q: A negatively charged ion with an excess electron moving with a velocity vx = 1.095 x103 m/s is…

Q: A particle with a charge of -1.24x10-8 C is moving with instantaneous velocity = (4.19×10¹ m/s)i +…

A: Given data : Charge on particle q = -1.24 × 10-8 C Velocity of charge particle v = (4.19 × 104…

Q: An ion with a charge to mass ratio of 1.10×104 C/kg travels perpendicular to magnetic field…

A: Given data: Charge to mass ratio of ion, qm=1.10×104 C/kg Magnetic field, B=9×10-1 T=0.9 T Radius…

Q: a particle with a charge of -3.00x10^-5 C is moving with instantaneous velocity v=(400m/s)i + (-500…

Q: Select the direction in which the particles are deflected upon entry into the magnetic fields shown:…

A: Given that:

Q: This positively charged particle has a charge of +25 nC and a velocity of 5300 m/s. It enters a…

A: Charge of particle, q = + 25nC = 25 x 10-9 C The velocity of particle, V = 5300 m/s Electric…

Q: A small charged particle (mass = 240 µkg ; charge = - 480 µcoul) travels through a region of space…

Q: Electrons are accelerated from rest in a CRT. These electrons now pass through a magnetic field of…

A: Write the relationship between the electric field and the magnetic field and substitute the required…

Q: See the attached figure for this problem. A charge of 6.46 x 10^6 C moves to the right as shown…

Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

GENERAL-PHYSICS-4TH-MODULE-2 - Word
Sign in
View
O Search
& Share
File
Home
Insert
Design
Layout
References
Mailings
Review
Help
L X
.. , 1. . . , . . 2 ... .. , 3. , . . , .
... . . 6
What I Have Learned
Instruction:
Solve the following problems neatly and completely in a one (1) whole sheet of intermediate or yellow
раper.
1. A particle with a charge of –1.24 x 108 C is moving with instantaneous velocity v =
(1.49 ×104m_)i+(-3.85×104m_)j. What is the force exerted on this particle by a magnetic
field (a) B` = (1.40 T)î+(-2.30 T)k and (b) B¯ = (-1.25 T)î+(2.00 T)j+(-3.50 T)K?
%3D
Page 8 of 17
4420 words
E English (Philippines)
+ 160%
10:24 PM
w
A O d)
08/05/2021

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

2. A particle with charge 3.94 x 10^-6 C moves at 7.73 x 10^6 m/s through a magnetic field of strength 2.46 T. The angle between the particle s velocity and the magnetic field direction is 54.3 degrees and the particle undergoes an acceleration of 15.0 m/s^2. What is the particle s mass? 19.5 kg 4.06 kg 4.5 kg 10.5 kg
An electron (me = 9.11 x 1031 kg, q = -1.602 x 10-19 C) travels at 3.0 x 10' m/s perpendicular to a 1.2 mT magnetic field. What is the magnitude of the electron's acceleration in m/s? Give your answer as only the numerical value in the Sl units specified. e is interpreted as x10^ for use with large or small values; 1.01e2 is interpreted as 1.01 x 102.
6. A particle with a charge of g = 1.6 x 10-19 C and a mass of 1.39 x 10-25 kg enters a mass spectrometer with a velocity of 4.0 x 105 ™. The particle strikes the detector 60 cm from where it entered the magnetic field. What is the strength of the magnetic field? 60 ст v = 4.0 x 105 m = 1.39 x 10-25 kg 4. O O O O O O O O O O O O. O O/O O O Q O O O aO O O OO O O O O Q. O O O O O O O O
A particle with a charge of -1.2 x 10-8 C is moving with instantaneous velocityv = (4.2 x 104 m/s) i + (-3.8 x 104 m/s) j. What are the components of the force exerted on this particle by a magnetic field B = (1.4 T) i + (2.4 T) k ?
2. A particle with charge 2.34 x 10^-6 C moves at 8.64 x 10^6 m/s through a magnetic field of strength 2.97 T. The angle between the particle s velocity and the magnetic field direction is 33.0 degrees and the particle undergoes an acceleration of 12.2 m/s^2. What is the particle s mass? Question 2 options: 15.9 kg 2.68 kg 2.4 kg 9.8 kg
5.
Part 2) A proton moving with a speed 3.84 × 10° m/s through a 2.99 T magnetic field experiences a force of magnitude 1.59 x 10-12 N. (Mass of the proton = 1.673 × 10¬27 kg, charge 1.602 × 10-19 C). What is the angle between the proton's velocity and the magnetic field? Part 3) What is the proton's acceleration? a = m/s?
29. At an instant in time, an electron has velocity, v = 100i - 300j + 200k km/s while it is in a magnetic field, B = 2i - 3j + 4k T. Find the acceleration of the electron at this instant. Use the vector table below to show any important vectors. Show only numerical results in the table. (m = 9.109 X 10" kg, q = -i.6 X 10'1º C) Vector i k
Current I = 30 A flows in a straight wire. An ion with charge Q = 3.2e-19 C is moving toward the wire, at distant r = 0.10 m, with speed v = The magnetic force on the ion is antiparallel to the current. What is the magnitude of the force? (in N) 6.00×106 m/s. A: 3.682x10-17 B: 4.897x10-17 OC: 6.513x10-17 OD: 8.662x10-17 E: 1.152x10-16 OF: 1.532x10-16 OG: 2.038×10-16 OH: 2.710×10-16