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1. A JM has a toy with a mass of 200 g, attached at one end of the string the toy hangs below his hand. If he exerts a force of 4.00 N upward on the string, determine the following: A.) the net force acting on the toy B.) acceleration of the toy

1. A JM has a toy with a mass of 200 g, attached at one end of the string the toy hangs below his hand. If he exerts a force of 4.00 N upward on the string, determine the following: A.) the net force acting on the toy B.) acceleration of the toy

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1. A JM has a toy with a mass of 200 g, attached at one end of the string the toy hangs below his hand. If he exerts a force of 4.00 N upward on the string, determine the following:

A.) the net force acting on the toy

B.) acceleration of the toy

Example is attached below. Please refer to it when answering.

2. Jemuel (30kg), starting from rest, gives his brother John Paul (30kg) a ride on a sled by exerting a force of 300 N (East) for 8.0 seconds while a frictional force of 100 N is acting on the opposite direction. Determine the following: a. acceleration of the sled together with Peter and his sister. b. the final velocity of the sled with Jemuel and John Paul when it reached 8.0s. c. distance traveled by the sled with Jemuel and John Paul in 8.0s. I. Given: V1 = 0 a. a = ? At = 8.0 s a = 0 b. Vr = ? c. d = ? Fa = 300 N East Ff = 200 N West m(combined) = 60kg II. Free – body diagram: N = 588 N Ff = 100 N Fa = 300 N W = 588 N III. Solution: b. Vi = V1 + at = 0 + (1.67 m/s2) (8.0 s) = 13.36 m/s c. d = Vịt + ½ at² = 0 + ½ (1.67 m/s2) (8.0 s)2 = ½ (1.67 m/s2) 64 s2) a. Fnet = Fa+Ff = 300N + (-200N) = 100N Fnet=ma a = Fnet/m = 100N/60kg = 1.67m/s? = 53.44 m
Transcribed Image Text:2. Jemuel (30kg), starting from rest, gives his brother John Paul (30kg) a ride on a sled by exerting a force of 300 N (East) for 8.0 seconds while a frictional force of 100 N is acting on the opposite direction. Determine the following: a. acceleration of the sled together with Peter and his sister. b. the final velocity of the sled with Jemuel and John Paul when it reached 8.0s. c. distance traveled by the sled with Jemuel and John Paul in 8.0s. I. Given: V1 = 0 a. a = ? At = 8.0 s a = 0 b. Vr = ? c. d = ? Fa = 300 N East Ff = 200 N West m(combined) = 60kg II. Free – body diagram: N = 588 N Ff = 100 N Fa = 300 N W = 588 N III. Solution: b. Vi = V1 + at = 0 + (1.67 m/s2) (8.0 s) = 13.36 m/s c. d = Vịt + ½ at² = 0 + ½ (1.67 m/s2) (8.0 s)2 = ½ (1.67 m/s2) 64 s2) a. Fnet = Fa+Ff = 300N + (-200N) = 100N Fnet=ma a = Fnet/m = 100N/60kg = 1.67m/s? = 53.44 m
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