**Problem Statement:**1. Refer to figure 2. The object (bottom left) lies on a table and experiences a 2.0 N horizontal force. Calculate its acceleration, and its final velocity after it travels 10.0 m.---**Figure 1 Explanation:**- A diagram is shown with a block labeled "0.50 kg" resting on a horizontal line, representing a table surface.---**Solution Steps:**1. **Calculate Acceleration:** - **Given:** - Mass (m) = 0.50 kg - Force (F) = 2.0 N - Using Newton's Second Law: F = ma - Acceleration (a) = F / m - **Calculation:** - a = 2.0 N / 0.50 kg = 4.0 m/s²2. **Calculate Final Velocity:** - **Given:** - Initial velocity (u) = 0 (starts from rest) - Distance (s) = 10.0 m - Use the equation of motion: v² = u² + 2as - **Calculation:** - v² = 0 + 2 * 4.0 m/s² * 10.0 m - v² = 80 - v = √80 - v = 8.94 m/s---**Conclusion:**The object's acceleration is 4.0 m/s², and its final velocity after traveling 10.0 m is approximately 8.94 m/s.

According to Newton's second law of motion, net force (F) is equal to mass (m) times acceleration…

Answered: 1. Refer to figure 2. The object…

1. Refer to figure 2. The object (bottom left) lies on a table and experiences a 2.0 N horizontal force. Calculate its acceleration, and its final velocity after it travels 10.0 m. Figure 1 0.50 kg

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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