1. A consumer advocacy group suspects that a local supermarket's 10-ounce packages of cheddar cheese weigh lessthan 10 ounces. The group took a random sample of 36 packages and found that the mean weight for the samplewas 9.955 ounces with a standard deviation of 0.15 ounces. At the 0.01 level of significance, is this in line with theclaim of the consumer advocacy group? (10 pts)Step 1: State the null and alternative hypothesis in Step 3: Compute test statisticwords.H0:H1:Step 2: Level of Significance and Critical Value/s and Step 4: Decision isRegionStep 5: State the conclusion.

Answered: Image /qna-images/answer/3cb9146d-282d-4609-922e-5608980978dd.jpg

Answered: 1. A consumer advocacy group suspects…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A student suspected the average cost of a Saturday night date was now greater than $30. To test her hypothesis, she randomly selected 16 men from the residence hall and asked how much they spent on a date last Saturday night. She found that in her sample, the average amount spent $32.75, the standard deviation was $5.25, and that the histogram of sample was unimodal and roughly symmetric. At , is there enough evidence to support her claim. What type of test would she use? One-sample proportion test One-sample t-test Two-sample proportion test Two-sample t-test
A simple random sample of 25 filtered 100 mm cigarettes is obtained, and the tar content of each cigarette is measured. The sample has a mean of 19.8 mg and a standard deviation of 3.18 mg. Use a 0.05 significance level to test the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg, which is the mean for unfiltered king size cigarettes. What do the results suggest, if anything, about the effectiveness of the filters?
A metropolitan transportation authority has set a bus mechanical reliability goal of 3,900 bus miles. Bus mechanical reliability is measured specifically as the number of bus miles between mechanical road calls. Suppose a sample of 100 buses resulted in a sample mean of 3,925 bus miles and a sample standard deviation of 225 bus miles. Complete parts (a) and (b) below. a. Is there evidence that the population mean bus miles is more than 3,900 bus miles? (Use a 0.05 level of significance.) Identify the critical value(s). Determine the test statistic. State the conclusion. Determine the p-value and interpret its meaning
A company claims that the mean weight of a certain type of chocolate bar they manufacture is 105 grams. A quality inspector would like to check whether this claim is correct. She takes a random sample of 74 chocolate bars and measures the weight of each bar using precision scales. The sample mean of the weights turns out to be 105.170 grams and the sample standard deviation is 0.912 grams. The inspector wishes to conduct a test at the .10 level of significance to determine whether these results provide evidence that the true mean weight is different from what the company claims. Calculate the p- value of the test. (Provide your answer as a number rounded to 4 decimals.)
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The U.S. Department of Agriculture reports that the mean cost of raising a child from birth to age 2 in arural area is $8390. You believe this value is incorrect, so you select a random sample of 900 children(age 2) and find that the mean cost is $8275. Assume the standard deviation for the cost of raising achild from birth to age 2 is $1540. Test your claim at the .05 level of significance
Assume the average amount of days a patient spends in hospital is believed to be 24 days and a hospital claims that their experience suggests that the average is actually lower. They randomly selected and followed 33 patients and found that the mean number of days was 21.5 with a standard deviation of 7.8. What is the test statistic and your conclusion for a=0.05? O A. Test statistic: -1.841 Conclusion: Not enough evidence to reject the null hypothesis O B. Test statistic: 1.841 Conclusion: Not enough evidence to reject the null hypothesis O C. Test statistic: 1.841 Conclusion: Reject the null hypothesis D. Test statistic: -1.841 Conclusion: Reject the null hypothesis
The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period. A random sample of 42 moviegoers from a large university revealed that the average number of movies seen per person was 9.9. The population standard deviation is 3.2 movies. At the 0.05 level of significance, can it be concluded that this represents a difference from the national average?
A food company claims that their packets of chips have an average weight of 50g. A consumer advocacy group takes a random sample of 25 packets and finds that the average weight is 49.8g with a standard deviation of 0.9g. Can the consumer advocacy group reject the claim of the food company at a significance level of 0.05?
0.1190 is wrong could you please kindly reattempt this?
The U.S. Department of Agriculture claims that the mean cost of raising a child from birth to age 2 by husband-wife families in the U.S. is $13,340. A random sample of 500 children (age 2) has a mean cost of $13,225 with a standard deviation of $1730. At a= 0.11 is there enough evidence to reject the claim? Use the p-value method. What is the p value?
In a test of the effectiveness of garlic for lowering cholesterol, 4949 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.40.4 and a standard deviation of 23.823.8. Use a 0.010.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 00. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Determine the test statistic. nothing (Round to two decimal places as needed.)

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