A test of sobriety involves measuring the subject's motor skills. Twenty randomly selected sober subjects take the test and produce a mean score of 41.0 with a standarddeviation of 3.7. At the 0.01 level of significance, test the claim that the true mean score for all sober subjects is equal to 35.0.The point estimate is:(rounded to 1 decimal place)The test statistic is:(rounded to 2 decimal places)The p-value is:(rounded to 4 decimal places)The Conclusionis type R (Reject the Null) or F (Fail to Reject the Null)

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Answered: A test of sobriety involves measuring…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Almost all medical schools in the United States require applicants to take the Medical College Admission Test (MCAT). On one exam, the scores of all applicants on the biological sciences part of the MCAT were approximately Normal with mean 9.5 and standard deviation 2.4. For applicants who actually entered medical school, the mean score was 10.8 and the standard deviation was 1.8. (a) What percent of all applicants had scores higher than 11? ANSWER: % (b) What percent of those who entered medical school had scores between 9 and 12? ANSWER: %
The distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches
Use z-scores to make the following comparison. A high school student took two college entrance exams, scoring 1110 on the SAT and 27 on the ACT. Suppose that SAT scores have a mean of 950 and a standard deviation of 130 while the ACT scores have a mean of 22 and a standard deviation of 4. Assuming the performance on both tests follows a normal distribution, determine which test the student did better on.
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
Consider a set of data in which the sample mean is 30.230.2 and the sample standard deviation is 7.87.8. Calculate the z-score given that x=31.4x=31.4. Round your answer to two decimal places.
In a t-test for paired samples, the one value that compares, for each person, her or his two measurements is called the . Difference score Deviation score Standard deviation Standard difference
Assume that the test scores for biostatistics midterm examination are normally distributed with a mean of 74 and a standard deviation of 10. i. Suppose that you receive a score of 88. What percent of the class received scores higher than yours? ii. Suppose that the teacher wants to limit the number of A grades in the class to no more than 20%. What would be the lowest score for an A?
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 night students, and the sample mean GPA is 2.83 with a standard deviation of 0.94. You sample 55 day students, and the sample mean GPA is 2.97 with a standard deviation of 0.92. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses?H0: Select an answer μ σ² μ₂ p μ₁ x̄₂ s² x̄₁ = Select an answer μ x̄₂ σ² μ₂ x̄₁ μ₁ s² p H1: Select an answer σ² μ x̄₁ s² p x̄₂ μ₁ μ₂ ? = < > ≤ ≠ ≥ Select an answer μ x̄₂ x̄₁ μ₂ σ² s² μ₁ p Based on the hypotheses, find the following:Test Statistic = Critical Values = ±± (Just enter the positive CV.)The correct decision is to Select an answer Reject the null hypothesis Fail to reject the null hypothesis The correct summary would be: Select an answer There is not enough…
On an intelligence test, the mean number of raw items correct is 236 and the standard deviation is 39. What are the raw (actual) scores on the test for people with IQs of (a) 119, (b) 81, and (c)100? To do this problem, first figure the Z score for the particular IQ score; then use that Z score to find the raw score. Note that IQ scores have a mean of 100 and a standard deviation of 15. (a) What is the raw (actual) score on the test for people with an IQ of 119?
You want to know if a treated sample mean, M, is significantly different from some hypothesized mean, however, you do not have access to the popuation standard deviation, so you estimate it by computing the standard deviation of the sample. Which stats test do you run? a. z test for determining position of a score, x, in a population. b. one-sample t test. c. independent-samples t test. d. z test for determining the position of a mean, M, in a sampling distribution.
After 84 students at a particular university take a psychological evaluation, the sample mean score on the test is calculated to be 117 with a standard deviation of 44. We are interested in testing whether or not the mean score of the students at this university is different than the published population average of 112. Calculate the value of the test statistic and then use that to determine the appropriate p-value. 0.5952 0.2976 0.1488 0.8512 1.7024 0.1488 0.0744

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