1. A conducting bar with resistance R = 89.7 mN slides down two conducting rails that have no electrical resistance. These rails make an angle 0 = 28.0° with the horizontal and are separated by a distance l = 64.0 cm, as shown. In addition, a uniform magnetic field B = 5.40 T is applied vertically upward. The bar is released from rest and slides down. (a) What must be the mass of the bar if the terminal velocity of the bar is 25.0 cm/s? (b) Using the mass you found, what will be the new terminal velocity if the magnetic field is turned so that it is perpendicular to the plane of the rails? R B a
1. A conducting bar with resistance R = 89.7 mN slides down two conducting rails that have no electrical resistance. These rails make an angle 0 = 28.0° with the horizontal and are separated by a distance l = 64.0 cm, as shown. In addition, a uniform magnetic field B = 5.40 T is applied vertically upward. The bar is released from rest and slides down. (a) What must be the mass of the bar if the terminal velocity of the bar is 25.0 cm/s? (b) Using the mass you found, what will be the new terminal velocity if the magnetic field is turned so that it is perpendicular to the plane of the rails? R B a
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Transcribed Image Text:1. A conducting bar with resistance R
electrical resistance. These rails make an angle 0 = 28.0° with the horizontal and are separated by
a distance l
= 89.7 m2 slides down two conducting rails that have no
64.0 cm, as shown. In addition, a uniform magnetic field B
5.40 T is applied
%3D
vertically upward. The bar is released from rest and slides down. (a) What must be the mass of the
bar if the terminal velocity of the bar is 25.0 cm/s? (b) Using the mass you found, what will be the
new terminal velocity if the magnetic field is turned so that it is perpendicular to the plane of the
rails?
R
B
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