A 0.750 m long solenoid, 0.024 m in diameter, has 9600 turns of wire. A current of 18 A flows in the solenoid. A particle with a charge of 3.0 x 10-10 C inside the solenoid travels perpendicular to the axis of the solenoid with a speed of 5.7 x 10 m/s. Find the magnitude of the magnetic force acting on the particle. (hint: find the magnetic field strength inside the solenoid first)
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- A proton traveling at 31.6° with respect to the direction of a magnetic field of strength 3.49 mT experiences a magnetic force of 6.46 × 101 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts. (a) Number 220783.95 Units m/s (b) Number i Units eVAn electron is traveling to the north with a speed of 3.5 x 10^6 m/s when a magnetic field is turned on. The strength of the magnetic field is 0.030 T, and it is directed to the left. What will be the direction and magnitude of the magnetic force?The horizontal component of the Earth's magnetic field has a magnitude of 1.6 x 105 T. An electron is shot vertically straight up from the ground with a speed of 2.1 x 106 m/s. What is the magnitude of the acceleration caused by the magnetic force? Ignore the gravitational force acting on the electron.