1. A compound curve whose long and short tangents intersect at station 10+255 has the following available given elements below. Determine its other Elements and the stationing (Sta PC, PCC, PT) of the given compound curve. Given: 1=32 degrees 12 = 24 degrees 30' M1 = 10.35 m %D M2 = 8.64 m
1. A compound curve whose long and short tangents intersect at station 10+255 has the following available given elements below. Determine its other Elements and the stationing (Sta PC, PCC, PT) of the given compound curve. Given: 1=32 degrees 12 = 24 degrees 30' M1 = 10.35 m %D M2 = 8.64 m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![1. A compound curve whose long and short
tangents intersect at station 10+255 has the
following available given elements below.
Determine its other Elements and the
stationing (Sta PC, PCC, PT) of the given
compound curve.
Given:
1=32 degrees
12 = 24 degrees 30'
M1 = 10.35 m
M2 = 8.64 m
2. The long and short tangents of a reverse
curve intersect at an angle of 40° at station
V. The Long tangent is 300 m while the short
tangent is 10.35 m. If the radius of the first
curve passing through station PC is 444.77
m, determine the values of lj and I2 of the
given reverse curve.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d0d94d5-bc05-4942-85b3-87d35f20e6f2%2F3377813e-4c61-4e61-9c95-7af4930efb20%2F75mi3db_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. A compound curve whose long and short
tangents intersect at station 10+255 has the
following available given elements below.
Determine its other Elements and the
stationing (Sta PC, PCC, PT) of the given
compound curve.
Given:
1=32 degrees
12 = 24 degrees 30'
M1 = 10.35 m
M2 = 8.64 m
2. The long and short tangents of a reverse
curve intersect at an angle of 40° at station
V. The Long tangent is 300 m while the short
tangent is 10.35 m. If the radius of the first
curve passing through station PC is 444.77
m, determine the values of lj and I2 of the
given reverse curve.
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