1. A car is parked 10 m from home for 10 minutes. Draw atime, velocity-time and acceleration-time graphs for the motion. Label allthe axes.Equdisplacement-2. A bus travels at a constant velocity of 12 m-s for 6 seconds. DrawIn tthe displacement-time, velocity-time and acceleration-time graph for themotion. Label all the axes.ingus3. An athlete runs with a constant acceleration of1m-s-2 for 4 s. Drawthe acceleration-time, velocity-time.motion. Accurate values are only needed for the acceleration-time andvelocity time graphs.displacement time graphs for the

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Description: 1. A car is parked 10 m from home for 10 minutes. Draw atime, velocity-time and acceleration-time graphs for the motion. Label allthe axes.Equdisplacement-2. A bus travels at a constant velocity of 12 m-s for 6 seconds. DrawIn tthe displacement-time

we will assume that the home is at the origin of the coordinate system. since the car is parked 10m…

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1. A car is parked 10 m from home for 10 minutes. Draw a displacement- time, velocity-time and acceleration-time graphs for the motion. Label all the axes.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Displacement, Velocity and Acceleration

In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.

Linear Displacement

The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.

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Question

1. A car is parked 10 m from home for 10 minutes. Draw a
time, velocity-time and acceleration-time graphs for the motion. Label all
the axes.
Equ
displacement-
2. A bus travels at a constant velocity of 12 m-s for 6 seconds. Draw
In t
the displacement-time, velocity-time and acceleration-time graph for the
motion. Label all the axes.
ing
us
3. An athlete runs with a constant acceleration of1m-s-2 for 4 s. Draw
the acceleration-time, velocity-time.
motion. Accurate values are only needed for the acceleration-time and
velocity time graphs.
displacement time graphs for the

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6. A car starts from rest and accelerates at a rate of 1.8 m/s² West for 15s. It goes at a constant velocity for 50s and then accelerates at a rate of 2.1m/s² East for 10 s. Use West as the positive direction. a. Draw an acceleration graph for this situation. Remember to quantitatively label your axes. a (m/812) t(s) 0-15 15-65 65-75 b. What is the change in velocity for each time interval? Av (m/s) t(s) Draw a velocity graph for this situation. Remember to quantitatively label your axes. v (m/s) E t(s) d. What is the total displacement between t-Os and t= 75 s?
5. Draw a distance vs. time graph for Melinda’s journey. Her home is located at 0 meters.Melinda is riding her bike over to her friend Sara’s house to complete an assignment. Her friend lives 5 km away. She accelerates away from her home for250 m in the next 2.5 minutes. She then rides at a constant speed of 300 m/min for 15 minutes. Melinda sees Sara’s house approaching so she slows downuntil she reaches her destination in the next 2.5 minutes. She stays at Sara’s house for 30 minutes while they work on the assignment. It is time to go home,Melinda rides home at a steady speed of 250 m/min for 10 minutes. Melinda is getting tired so she slows down for 250 m during the next 5 minutes thenstops for 2.5 minutes to have a drink. Realizing it’s getting late, she had to speed up 1 km in the next 5 minutes then rides at a constant speed of 300 m/minfor 2.5 minutes. Almost home, she decelerates for the next 10 minutes until she reaches her house.
If the velocity is constant towards the right direction, the graph of displacement x vs time t is a A. line with a positive slope. B. line with negative slope. C. parabola in the first quadrant. O D. parabola in the 4th quadrant. An object is moving towards the right direction. Velocity is constant. The graph of velocity vs time t is a line O A. along the t axis B. parallel to the t axis C. parallel to the v axis. O D. with nonzero slope. Velocity of a moving object is towards the right. Velocity is constant. The graph of acceleration a vs time t is a A. line parallel to the acceleration a axis. B. line along the acceleration a axis. C. line along the t-axis. OD.line with positive slope.
1. Refer to the velocity-time graph of a jogger. The positive direction is away from the jogger's home. Rank the four distances for the time intervals, A, B, C, D in decreasing order. Explain your answer. 15 10 C 40 50 30 20 Time (s) 0. 10 20 (s/w) pe 25
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